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Svet_ta [14]
1 year ago
9

Consider the reaction, 2 C3H8O(g) + 9 O2(g) → 6 CO2(g) + 8 H2O(g).

Chemistry
1 answer:
Serjik [45]1 year ago
8 0

When 12 moles of O₂ (g) react with C₃H₈O (g) then 8 moles of CO₂ (g) is produced. This is the chemical combustion reaction of propanol producing vapor of CO₂.

<h3>How to calculate the amount of CO₂ produced?</h3>

Alcohols undergo combustion reaction in the presence of oxygen gas to produce vapor of CO₂ and water.

In the given equation,

2 C₃H₈O (g) + 9 O₂ (g) → 6 CO₂ (g) + 8 H₂O (g)

To calculate the number of moles of CO₂ produced, first we have to balance the equation:

Divide the equation by 2

C₃H₈O (g) + 9/2 O₂ (g) → 3 CO₂ (g) + 4 H₂O (g)

Calculate the number of moles of CO₂ (g) produced with 1 mol of O₂ (g)

9/2 O₂ (g) → 3 CO₂ (g)

1 O₂ (g) → 3÷9/2 CO₂ (g) = 0.66 mol CO₂ (g)

For 12 mol of O₂ (g),

12 × 0.66 = 8 mol CO₂ (g)

Therefore, 8 mol of CO₂ (g) is produced from 12 mol of O₂ (g).

Learn more about Combustion reaction here:

brainly.com/question/14335621

#SPJ1

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4 moles of hydrogen react with 5 moles of oxygen to form water, identify the excess reagent?
Fynjy0 [20]

Answer:

Excess Reagent = oxygen

Explanation:

Limiting reagent: The substance that is totally consumed when the reaction is completed.

Excess reagent: The substance left after the limiting reagent is consumed completely

The balanced chemical equation for formation of water is as follow:

2H_{2}+O_{2}\rightarrow 2H_{2}O

This means when 2 moles of hydrogen reacts with 1 mole of oxygen, 2 moles of water is produced.

Hence the ratio in which hydrogen and oxygen gas reacts is 2:1

Now if 2 mole hydrogen require 1 mole of oxygen ,then 4 mole hydrogen need 2 mole of oxygen.

H_{2}:O_{2}=2:1

or

H_{2}:O_{2}=4:2

Here 5 mole of oxygen is reacting but only 2 mole is required .

Oxygen is in excess.

5 0
3 years ago
Please help me for question 1 and 2
likoan [24]

Answer:-

1) 6 mol

2) Mo

Explanation: -

Mass of Ozone = 48 g

Chemical formula of ozone = O3

Molar mass of Ozone O 3 = 16 x 3 = 48 g mol-1

Number of moles of ozone = Mass / molar mass

= 48 g / 48 g mol-1

= 1 mol

According to Avogadro’s law, 1 mole of a substance has 6.02 x 10^ 22 molecules.

So 1 mol of O3 has 6.02 x 10^ 22 molecules of ozone.

Now each Ozone molecule has 3 atoms of oxygen.

So, 1 mol of ozone has 3 x 6.02 x 10^22 atoms of oxygen.

Sodium must have 2 x 3 x 6.02 x 10^22 atoms as per the question.

According to Avogadro’s law, 6.02 x 10^ 22 atoms are in 1 mol of sodium

So, for 2 x 3 x 6.02 x 10^22 atoms, there should be (1/ 6.02 x 10^ 22) x 2 x 3 x 6.02 x 10^22

= 6 mol of sodium.

b)

Let the mass of M be m g

Formula of hexafluoride = MF6.

Mass of the hexafluoride = g + 6 x 19

= m + 114

Mass of M=0.250g

Moles of M = 0.250/m

Mass of MF6= 0.547g

Moles of MF6 = 0.547/ (m + 114)

We know 1 mole of M gives 1 mole of MF6.

0.250/m moles of M gives 0.250/m moles of MF6.

But number of moles of MF6 = 0.547/ (m + 114)

Thus

0.250/m = (0.547)/ (m +114))

0.250m + 0.250 x 114 = 0.547m

m = 0.250 x 114 / (0.547 -0.250)

= 96

We see from the given data that Mo is 96.

So M is Mo.

4 0
3 years ago
What would be the greatest difference in using an open ceramic coffee mug rather than an insulated mug with a lid as a calorimet
STALIN [3.7K]

Answer:

Hi. Increased evaporation would be the greatest difference.

Explanation:

Have you ever had a drink in a mug with a lid? When you would remove the lid, all of the liquid on the lid is the liquid that would evaporate if there was no lid.

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