When 12 moles of O₂ (g) react with C₃H₈O (g) then 8 moles of CO₂ (g) is produced. This is the chemical combustion reaction of propanol producing vapor of CO₂.
<h3>How to calculate the amount of CO₂ produced?</h3>
Alcohols undergo combustion reaction in the presence of oxygen gas to produce vapor of CO₂ and water.
In the given equation,
2 C₃H₈O (g) + 9 O₂ (g) → 6 CO₂ (g) + 8 H₂O (g)
To calculate the number of moles of CO₂ produced, first we have to balance the equation:
Divide the equation by 2
C₃H₈O (g) + 9/2 O₂ (g) → 3 CO₂ (g) + 4 H₂O (g)
Calculate the number of moles of CO₂ (g) produced with 1 mol of O₂ (g)
9/2 O₂ (g) → 3 CO₂ (g)
1 O₂ (g) → 3÷9/2 CO₂ (g) = 0.66 mol CO₂ (g)
For 12 mol of O₂ (g),
12 × 0.66 = 8 mol CO₂ (g)
Therefore, 8 mol of CO₂ (g) is produced from 12 mol of O₂ (g).
Learn more about Combustion reaction here:
brainly.com/question/14335621
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