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Lubov Fominskaja [6]
1 year ago
13

You burn a 3.4 g cube of tofu to warm 12 g of water, which increases the temperature of the water 7 °C. How many calories of hea

t does the water absorb?Assume there is no heat loss. Round your answer to the nearest 0.1.(1 cal=4.184 J)
Chemistry
1 answer:
Murrr4er [49]1 year ago
4 0

Answer:

Water absorbs 84cal.

Explanation:

The given information about water is:

- mass of water (m): 12g

- change in temperature (ΔT): 7°C

With the given information, and the specific heat of water (c=1cal/g.°C), we can calculate the aeat that water absorbs, using the heat formula:

\begin{gathered} Q=m*c*\Delta T \\ Q=12g*1\frac{cal}{g*\degree C}*7\degree C \\ Q=84cal \end{gathered}

So, water absorbs 84cal.

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A silver cube with an edge length of 2.38 cm and a gold cube with an edge length of 2.79 cm are both heated to 81.9 ∘C and place
never [62]

Answer:

The final temperature of the water when thermal equilibrium is reached is 23.54 ⁰C

Explanation:

<u>Given data;</u>

edge length of silver, a = 2.38 cm = 0.0238 m

edge length of gold, a = 2.79 cm = 0.0279 m

final temperature of silver, t = 81.9 ° C

final temperature of Gold, t = 81.9 ° C

initial temperature of water, t = 19.6 ° C

volume of water, v =  109.5 mL = 0.0001095 m³

<u>Known data:</u>

density gold 19300 kg/m³

density silver 10490 kg/m³

density water 1000 kg/m³

specific heat gold is 129 J/kgC

specific heat silver is 240 J/kgC

specific heat water is 4200 J/kgC

<u>Calculated data</u>

Apply Pythagoras theorem to determine the side of each cube;

Silver cube;

let L be the side of the silver cube

Taking the cross section of the cube (form a right angled triangle), the edge  length forms the <em>hypotenuse side</em>.

L² + L² = 0.0238²

2L² = 0.0238²

L² = 0.0238² / 2

L² = 0.00028322

L = √0.00028322

L = 0.0168

Volume of cube = L³

Volume of the silver cube = (0.0168)³ = 4.742 x 10⁻⁶ m³

Gold cube;

let L be the side of the gold cube

L² + L² = 0.0279²

2L² = 0.0279²

L² = 0.0279² / 2

L² = 0.0003892

L = √0.0003892

L = 0.0197

Volume of cube = L³

Volume of the silver cube = (0.0197)³ = 7.645 x 10⁻⁶ m³

Mass of silver cube;

density = mass / volume

mass = density x volume

mass of silver cube = 10490 (kg/m³) x 4.742 x 10⁻⁶ (m³) = 0.0497 kg

Mass of Gold cube

mass of gold cube = 19300 (kg/m³) x 7.645 x 10⁻⁶ (m³) = 0.148 kg

Mass of water

mass of water = 1000 (kg/m³) x 0.0001095 (m³) = 0.1095 kg

Let the heat gained by cold water be  Q₁

Let the heat lost  by silver cube = Q₂

Let the heat lost  by gold cube = Q₃

Let the final temperature of water = T

Q₁  = 0.1095 kg x 4200 J/kgC x (T–19.6)

Q₂ = 0.0497 kg x 240 J/kgC x (81.9–T)

Q₃ = 0.148 kg x 129 J/kgC x (81.9–T)

At thermal equilibrium;

Q₁ = Q₂ + Q₃

0.1095 x 4200  (T–19.6)  = 0.0497 x 240 x (81.9–T)  + 0.148 x 129 x (81.9–T)

459.9 (T–19.6) = 11.928 (81.9–T) + 19.092(81.9–T)

459.9T - 9014.04 = 976.9032 - 11.928T + 1563.6348 - 19.092T

459.9T + 11.928T + 19.092T = 9014.04  + 976.9032 + 1563.6348

490.92T = 11554.578

T = 11554.578 / 490.92

T = 23.54 ⁰C

Therefore, the final temperature of the water when thermal equilibrium is reached is 23.54 ⁰C

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3 years ago
A sample of aluminum weighs 100 grams and has a volume of 37.03 cm. What is the density of
Alexxandr [17]

Answer:

2.7005 g/cm²

explanation: as we know density=mass/volume

6 0
3 years ago
What determines which element an atom is?
Lana71 [14]
C) number of protons.
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Why does the mass number for an element differ from the average atomic mass for the element?​
yarga [219]

Answer:

the mass number is the number of protons and neutrons added and the average atomic mass is the weight of the protons and neutrons

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The transfer of pollen grains from another of a male to the stigma of female flower
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pollination is the proces called

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