Answer:
This new temperature is 97.7 mL
Explanation:
Step 1: Data given
Volume = 0.225 L
STP = 1 atm and 273 K
Pressure = 2.7 atm
Temperature = 320 K
Step 2: Calculate new volume
(P1*V1)/T1 = (P2*V2)/T2
⇒with P1 = the pressure at STP = 1 atm
⇒with V1 = the volume = 0.225 L
⇒with T1 = the temperature at STP = 273 K
⇒with P2 = the new pressure = 2.7 atm
⇒with V2 = the new volume = TO BE DETERMINED
⇒with T2 = the new temperature = 320 K
(1atm *0.225 L)/273 K = (2.7 atm * V2) /320 K
8.24 * 10^-4 = 2.7 * V2 / 320K
2.7V2 = 0.264
V2 = 0.0977 L = 97.7 mL
This new temperature is 97.7 mL
