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Olin [163]
1 year ago
8

What is the relationship between nucleic acids and nucleotides?

Chemistry
1 answer:
maw [93]1 year ago
7 0

The nucleotides are monomers of nucleic acid.

The nucleic acids are the macro molecules. They are two types- DNA and RNA. The nucleic acid, DNA consists of nucleotide which are monomers of the DNA. The nucleotides have three components such as pentose sugar, nitrogen bases, and phosphate.

They are the backbone of DNA. DNA is the polymer of nucleotide, and this DNA is coming under nucleic acids. The nucleotides form DNA, and DNA forms the nucleic acid. They are interlinked with each other.

Nucleic acids are the center for storing all the information. The deoxyribose nucleic acid or DNA is the center for storing all the genetic information.

The genetic material is inherited from the parents to the children. The characters are transferred from one generation to another.

The characters such as hair color, hair type, eye color are some of the genetic information that is carried from one generation to another via nucleic acids.

Nucleotide is the basic unit of nucleic acid (DNA and RNA) which store the genetic code of the cell.

It consists of sugar base (ribose or deoxyribose), nitrogenous base (A, T, G, C and U), and phosphate group.

Nucleotides (specially ATP) provides the energy for most of the cellular processes.

Therefore, with the above statements we got to know that both nucleic acid and nucleotides are genetically modified.

To know more about nucleic acid, refer: brainly.com/question/29794338

#SPJ4

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What is the total mass of 2.0 moles of diatomic hydrogen?
sladkih [1.3K]

diatomic hydrogen is written as H2                                                                                (2.02 grams H2) <------- if each hydrogen atom is 1.01 grams, then two hydrogen atoms are 2.02 grams                                                                                                                  2.0 moles H2 X 2.02 grams H2                                                                                             ------------- (divide to cancel moles)   = 4.04 grams/mole H2 ÷ one mole = 4.04 grams H2

                                                          

7 0
3 years ago
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Write Lewis structures for the following molecules: (a) ICl, (b) PH3, (c) P4 (each P is bonded to three other P atoms), (d) H2S,
spin [16.1K]

Answer :  The Lewis-dot structure for the following molecules are shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

Now we have to determine the Lewis-dot structure for the following molecules.

(a) The given molecule is, ICl

As we know that iodine and chlorine have '7' valence electrons.

Therefore, the total number of valence electrons in ICl = 7 + 7 = 14

According to Lewis-dot structure, there are 2 number of bonding electrons and 12 number of non-bonding electrons.

(b) The given molecule is, PH_3

As we know that phosphorous has '5' valence electrons and hydrogen has '1' valence electrons.

Therefore, the total number of valence electrons in PH_3 = 5 + 3(1) = 8

According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.

(c) The given molecule is, P_4

As we know that phosphorous has '5' valence electrons.

Therefore, the total number of valence electrons in P_4 = 4(5) = 20

According to Lewis-dot structure, there are 6 number of bonding electrons and 14 number of non-bonding electrons.

(d) The given molecule is, H_2S

As we know that sulfur has '6' valence electrons and hydrogen has '1' valence electrons.

Therefore, the total number of valence electrons in H_2S = 6 + 2(1) = 8

According to Lewis-dot structure, there are 4 number of bonding electrons and 4 number of non-bonding electrons.

(e) The given molecule is, N_2H_4

As we know that nitrogen has '5' valence electrons and hydrogen has '1' valence electrons.

Therefore, the total number of valence electrons in N_2H_4 = 2(5) + 4(1) = 14

According to Lewis-dot structure, there are 10 number of bonding electrons and 4 number of non-bonding electrons.

(f) The given molecule is, HClO_3

As we know that chlorine has '7' valence electrons, oxygen has '6' valence electrons and hydrogen has '1' valence electrons.

Therefore, the total number of valence electrons in HClO_3 = 1 + 7 + 3(6) = 26

According to Lewis-dot structure, there are 12 number of bonding electrons and 14 number of non-bonding electrons.

(g) The given molecule is, COBr_2

As we know that bromine has '7' valence electrons, oxygen has '6' valence electrons and carbon has '4' valence electrons.

Therefore, the total number of valence electrons in COBr_2 = 4 + 6 + 2(7) = 24

According to Lewis-dot structure, there are 8 number of bonding electrons and 16 number of non-bonding electrons.

3 0
2 years ago
A mixture is made by combining 1.62 lb of salt and 5.20 lb of water.
Galina-37 [17]

Answer:

oof idk I would suggest looking at an example and try going off that

7 0
3 years ago
True or False? Some solids after mixing with other solids can be distinguished from each other
katen-ka-za [31]

Answer:

True

Explanation:

Depends of the size and comparison

4 0
2 years ago
Read 2 more answers
A cubic piece of platinum metal (specific heat capacity = 0.1256 J/°C・g) at 200.0°C is dropped into 1.00 L of deuterium oxide ('
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Answer:

a=5.65cm

Explanation:

Hello,

In this case, for this heat transfer process in which the heat lost by the hot platinum is gained by the cold deuterium oxide based on the equation:

Q_{Pt}=-Q_{Deu}

We can represent the heats in terms of mass, heat capacities and temperatures:

m_{Pt}Cp_{Pt}(T_f-T_{Pt})=-m_{Deu}Cp_{Deu}(T_f-T_{Deu})

Thus, we solve for the mass of platinum:

m_{Pt}=\frac{-m_{Deu}Cp_{Deu}(T_f-T_{Deu})}{Cp_{Pt}(T_f-T_{Pt})} \\\\m_{Pt}=\frac{-1.00L*1110g/L*4.211J/(g\°C)*(41.9-25.5)\°C}{0.1256J/(g\°C)*(41.9-200.0)\°C} \\\\m_{Pt}=3860.4g

Next, by using the density of platinum we compute the volume:

V_{Pt}=\frac{3860.4g}{21.45g/cm^3}\\ \\V_{Pt}=180cm^3

Which computed in terms of the edge length is:

V=a^3

Therefore, the edge length turns out:

a=\sqrt[3]{180cm^3}\\ \\a=5.65cm

Best regards.

6 0
3 years ago
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