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uranmaximum [27]
1 year ago
7

hello, I need help with a 25 question test! Which statement is an example of heat transfer by convection?Question 4 options:Jane

's feet burned as she walked across the hot beach sand.Hot air from the sand rose and was replaced by cool air blowing in from the ocean as a sea breeze.The black asphalt of the parking lot was much warmer than the green grass surrounding the lot.People were scattered across the beach, sitting on chairs and towels, warming themselves in the bright sunshine.
Physics
1 answer:
garri49 [273]1 year ago
3 0
\begin{gathered} Heat\text{ transfer by }convection\text{ }occurs\text{ on fluids like air or water, hence, an example of heat } \\ \text{transfer by convection is: "Hot air from the sand rose and was replace by cool aire blowing} \\ in\text{ from the ocean as a sea bre}eze." \end{gathered}

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Answer:

2.84\cdot 10^{-8} m

Explanation:

Due to the law of conservation of energy, the energy of the emitted X-ray photon is equal to the energy lost by the electron.

The initial kinetic energy of the electron is:

K_i = \frac{1}{2}mv_i^2 = \frac{1}{2}(9.11\cdot 10^{-31}kg)(5.90\cdot 10^6 m/s)^2=1.59\cdot 10^{-17}J

The electrons decelerates to 3/4 of its speed, so the new speed is

v_f = \frac{3}{4}v_i = \frac{3}{4}(5.90\cdot 10^6 m/s)=4.425\cdot 10^6 m/s

So the final kinetic energy is

K_f = \frac{1}{2}mv_f^2=\frac{1}{2}(9.11 \cdot 10^{-31} kg)(4.425\cdot 10^6 m/s)^2=8.9\cdot 10^{-18} J

So, the energy lost by the electron, which is equal to the energy of the emitted photon, is

E=K_i - K_f =1.59\cdot 10^{-17} J-8.9\cdot 10^{-18} J=7\cdot 10^{-18} J

The wavelength of the photon is related to its energy by

\lambda=\frac{hc}{E}

where h is the Planck constant and c the speed of light. Substituting E, we find

\lambda=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{7\cdot 10^{-18} J}=2.84\cdot 10^{-8} m

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Complete question is;

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We can be solve this by choosing a single vector normal to ALL of the possible velocity vectors of the rotating object in that plane.

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