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uranmaximum [27]
1 year ago
7

hello, I need help with a 25 question test! Which statement is an example of heat transfer by convection?Question 4 options:Jane

's feet burned as she walked across the hot beach sand.Hot air from the sand rose and was replaced by cool air blowing in from the ocean as a sea breeze.The black asphalt of the parking lot was much warmer than the green grass surrounding the lot.People were scattered across the beach, sitting on chairs and towels, warming themselves in the bright sunshine.
Physics
1 answer:
garri49 [273]1 year ago
3 0
\begin{gathered} Heat\text{ transfer by }convection\text{ }occurs\text{ on fluids like air or water, hence, an example of heat } \\ \text{transfer by convection is: "Hot air from the sand rose and was replace by cool aire blowing} \\ in\text{ from the ocean as a sea bre}eze." \end{gathered}

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A small metal cube measures 2.5 cm on one side. The mass of the cube is 1129.56 g. What is the density of the cube?
attashe74 [19]

-- volume = (length)(width)(height)

-- Since the cube is a cube, its three dimensions are all the same number.

Volume = (2.5cm)(2.5cm)(2.5cm)

Volume = 15.625 cubic cm

-- density = (mass) / (volume)

Density = (1129.56g) / (15.625cm^3)

Density = 72.3 g/cm^3

(roughly 3.2 TIMES the density of the most dense naturally occurring substance on Earth)

8 0
3 years ago
A tree is 257 ft high. To the nearest tenth of a meter, how tall is it in meters? There are 3.28 ft in 1 m.
olga2289 [7]

Answer:

Height of tree = 78.35 meters.

Explanation:

We have

          1 meter = 3.28 feet

That is

          1 ft = \frac{1}{3.28}=0.3048m

Here height of tree = 257 ft

Height of tree = 257 x 0.3048 = 78.35 m

Height of tree = 78.35 meters.

7 0
3 years ago
How does gravity affect the motions of Earth and the Moon?
RoseWind [281]

Answer:

The Sun's gravitational pull keeps our planet orbiting the Sun. The motion of the Moon is affected by the gravity of the Sun and Earth. Moon's gravity pulls on the Earth and makes the tides rise and fall.

8 0
2 years ago
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S Suppose you wish to fabricate a uniform wire from a mass m of a metal with density rhom and resistivity rho. If the wire is to
Gre4nikov [31]

By calculation, the diameter of the wire  is 2.8 * 10^-3 m.

<h3>How do we obtain the length?</h3>

The following data are given in the question;

Mass of the wire = 1.0 g or 1 * 10^-3 Kg

Resistance = 0.5 ohm

Resistivity of copper = 1.7 * 10^-8 ohm meter

Density of copper = 8.92 * 10^3 Kg/m^3

V = m/d

But v = Al

Al = m/d

A = m/ld

Resistance = ρl/A

= ρl/m/ld =

l^2 = Rm/ρd

l = √ Rm/ρd

l = √0.5 * 1 * 10^-3 / 1.7 * 10^-8 * 8.92 * 10^3

l = 1.82 m

A = πr^2

Also;

A = m/ld

A = 1 * 10^-3 Kg / 1.82 m * 8.92 * 10^3 Kg/m^3

Area of the wire = 6.2 * 10^-5 m^2

r^2 = A/ π

r = √A/ π

r = √6.2 * 10^-5 m^2/3.142

r = 1.4 * 10^-3 m

Diameter = 2r = 2( 1.4 * 10^-3 m) = 2.8 * 10^-3 m

Learn more about resistivity:brainly.com/question/14547003

#SPJ4

Missing parts;

Suppose you wish to fabricate a uniform wire from 1.00g of copper. If the wire is to have a resistance of R=0.500Ω and all the copper is to be used, what must be (a) the length and (b) the diameter of this wire?

6 0
1 year ago
HELP!!!!! Please hurry up
Degger [83]

it's def. TRUE. i got the same question and i got it right

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3 years ago
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