The advantage of an interferometer is that
1 answer:
You might be interested in
Answer:
Change in kinetic energy: 13479.77 J
Percentage change in kinetic energy = 99.85%
Explanation:
Change in momentum when the projectile becomes embedded in the block will be 0.
This means:
here subscript P means projectile, and subscript B means block.
Solving this equation we get:
(0.075 * 600) + (50 * 0) = (0.075 + 50) * V
Using this velocity we can compute the change in kinetic energy:
Initial kinetic energy = 0.5 * m * v^2
Initial kinetic energy = 0.5 * 0.075 * 600^2
Initial kinetic energy = 13500 J
Final Kinetic energy = 0.5 * m * v^2
Mass (m) = mass of block + mass of projectile = 50.075 kg
Final velocity v = 0.899 m/s
Final Kinetic Energy = 0.5 * 50.075 * 0.899^2
Final Kinetic Energy = 20.235 J
Change in kinetic energy = 13500 - 20.235 = 13479.77 J
Percentage change of kinetic energy = (13479.77 / 13500) * 100
Percentage change of kinetic energy = 99.85 %
Answer:
volume flow rate Q = 53.23 in³/s
Explanation:
given data
diameter = 4.22 inches
length = 75 inches
screw rotates = 65 revolutions per minute
depth = 0.23 in
flight angle = 21.4 degrees
head pressure = 705 lb/in²
viscosity = 145 x lb·sec/in²
solution
we get here volume flow rate of platstic in barrel that is express as
volume flow rate Q = volume flow rate of die - volume flow of extruder barrel ................1
here
volume flow rate extruder barrel is
flow rate =
flow rate = 60.10
and
volume flow rate of die is express as
volume flow rate = 0.5 × π² × D² × Ndc × sinA × cosA .............2
put here value and w eget
volume flow rate = 0.5 × π² × 4.22² × 0.23 × 1 × sin21.4 × cos21.4
volume flow rate = 6.866
so put value in equation 1 we get
volume flow rate Q = 60.10 - 6.866
volume flow rate Q = 53.23
Answer:
the projected volumetric flow rate of fuel for each of the two Dreamliner engines is 0.005 m³/s
Explanation:
Given the data in the question;
First we determine the fuel economy of Boeing 767
Range = 12,000 km
fuel capacity = 90,000 L
so, fuel economy of Boeing 767 will be
η = Range / fuel capacity
η = ( 12,000 km / 90000 L ) ( 1000m / 1 km) ( 3.7854 L/gal × 264.2 gal/m² )
η = 133,347.024 m/m³
Now, Boeing 787 is 20% more fuel efficient than Boeing 767
so fuel economy of Boeing 787 will be;
⇒ (1 - 20%) × fuel economy of Boeing 767
⇒ (1 - 0.2) × 133,347.024 m/m³
⇒ 0.8 × 133,347.024 m/m³
⇒ 106,677.6 m/m³
Hence, fuel economy of Boeing 787 dream line engine is
⇒ 106,677.6 m/m³ / 2 = 53,338.8 m/m³
Next, we find the velocity of Boeing 787
= Mach number of 787 × speed of sound
given that; Mach number is 0.85 and speed of sound is 700 mph
we substitute
= (0.85 × 700 mph) × ( 1 hr / 3600 s ) × ( 1609 m / 1 mile )
= 265.9319 m/s
Now, to get the Volume flow rate for each dream liner engine { Boeing 787 };
Volumetric flow rate = velocity of flight / fuel economy
we substitute
= 265.9319 m/s / 53,338.8 m/m³
= 0.0049857 ≈ 0.005 m³/s
Therefore, the projected volumetric flow rate of fuel for each of the two Dreamliner engines is 0.005 m³/s