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Alexxx [7]
1 year ago
7

the aluminum sample is dissolved in hcl and h2 gas is produced and collected over water. the volume of h2 gas produced is 73.8 m

l. what is the volume of gas, in liters? ***do not enter units with your answer. do not use scientific notation. correct significant figures are required\.\***
Chemistry
1 answer:
Gnesinka [82]1 year ago
5 0

The volume of gas is 62.2 L

The balance chemical equation is

2Al + 6 H+ → 2Al3+  + 3H2

n al/nH2 = 2/3

nH2 = 3/2 nAl

nAl = given mass / molar mass = 42/27 = 1.56 mol

nH2 = 3 × 1.56/2 = 2.34 mol

so, accordingly to ideal generation PV = nRT

V = nRT/P

T = 30 degree celsius = 303K

V = 62.2 L

The amount of occupied three-dimensional space is measured in volume. It is typically expressed quantitatively using SI-derived units (such the cubic meter and liter) as well as other imperial or US-standard units (such as the gallon, quart, cubic inch). By the definition of length, volume and length are connected (cubed). The volume of a container is commonly understood to be its carrying capacity, or the amount of fluid (liquid or gas) that it could hold, as opposed to how much actual space the container occupies.

In the past, standardized containers were used to calculate volume first, followed by naturally occurring vessels of a similar shape. A number of simple three-dimensional shapes have volumes that can be calculated using mathematical methods.

Learn more about volume here:

brainly.com/question/24189159

#SPJ4

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if a liquid is heated and the temperature at which it boils is measured, the ? property is beingm easured.
Thepotemich [5.8K]
You are measuring an Intensive property
5 0
3 years ago
SOMEONE PLEASE HELP
Zinaida [17]

Answer:

6. 7870 kg/m³ (3 s.f.)

7. 33.4 g (3 s.f.)

8. 12600 kg/m³ (3 s.f.)

Explanation:

6. The SI unit for density is kg/m³. Thus convert the mass to Kg and volume to m³ first.

1 kg= 1000g

1m³= 1 ×10⁶ cm³

Mass of iron bar

= 64.2g

= 64.2 ÷1000 kg

= 0.0642 kg

Volume of iron bar

= 8.16 cm³

= 8.16 ÷ 10⁶

= 8.16 \times 10^{ - 6} \:  kg

\boxed{density =  \frac{mass}{volume} }

Density of iron bar

=  \frac{0.0642}{8.16 \times 10^{ - 6} }

= 7870 kg/m³ (3 s.f.)

7.

\boxed{mass = density \:  \times volume}

Mass

= 1.16 ×28.8

= 33.408 g

= 33.4 g (3 s.f.)

8. Volume of brick

= 12 cm³

= 12  \times  10^{ - 6}  \: m^{3}  \\  = 1.2 \times 10^{ - 5}  \: m ^{3}

Mass of brick

= 151 g

= 151 ÷ 1000 kg

= 0.151 kg

Density of brick

= mass ÷ volume

=  \frac{0.151} {1.25 \times 10^{ - 5} }  \\  = 12600 \: kg/ {m}^{3}

(3 s.f.)

6 0
3 years ago
A
DIA [1.3K]
  • V_1=49.8mL
  • T_1=18°C=291K
  • T_2=83°C=356K

Using Charles law

\\ \sf\longmapsto V_1T_2=V_2T_1

\\ \sf\longmapsto V_2=V_1T_2\div T_1

\\ \sf\longmapsto V_2=\dfrac{49.8(356)}{291}

\\ \sf\longmapsto V_2=\dfrac{17728.8}{291}

\\ \sf\longmapsto V_2=60.9mL

5 0
3 years ago
Can someone help me with this question ASAP
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Aye i can’t see the full question dawg, you gotta send a full picture of it
6 0
2 years ago
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