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solmaris [256]
1 year ago
5

A bullet is fired horizontally from a height of 47 m and hits the ground

Physics
1 answer:
wolverine [178]1 year ago
3 0

The velocity the bullet used in leaving the gun is 586 m/s (Option 1)

We'll begin by obtaining the time taken for the bullet to hit the ground. This is illustrated below::::

  • Height (h) = 47 m
  • Acceleration due to gravity (g) = 10 m/s²
  • Time (t) =?

h = ½gt²

47 = ½ × 10 × t²

47 = 5 × t²

Divide both side by 5

t² = 47 / 5

Take the square root of both side

t = √(47 / 5)

t = 3.07 s

Finally, we shall determin the the velocity. This is illustrated below:

  • Horizontal distance (s) = 1800 m
  • Time (t) = 3.07 s
  • Velocity (u) = ?

s = ut

1800 = u × × 3.07

Divide both sides by 3.07

u = 1800 / 3.07

u = 586 m/s

Thus, the velocity the bullet used in leaving the gun is 586 m/s (Option 1)

Learn more about motion under gravity:

brainly.com/question/20385439

brainly.com/question/22719691

#SPJ1

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Answer:

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Explanation:

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v₈₀ = √(2(1280) /0.5) = 69.5 m/s

t₈₀  = h/v(avg) = 80 / (½(80 + 69.5)) = 1.07 s

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