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allsm [11]
3 years ago
11

Given the following access-control list: access-list 90 deny 10.168.7.0 0.0.0.255 access-list 90 permit host 10.168.7.10 access-

list 90 permit host 10.168.7.11 access-list 90 permit host 10.168.7.12 access-list 90 deny any What would be the end result if the network security engineer applies access-list 90 to the inbound interface of FastEthernet 0/3? Group of answer choices A. The access-list will permit host 10.168.7.10 to pass through the router. B. The access-list will permit host 10.168.7.15 to pass through the router. C. Denial of service for this network because the rules are not placed in the correct order. D. Both hosts 10.168.7.10 and 10.168.7.11 will be permitted. E. The access-list will generate an error message.
Engineering
1 answer:
Yuri [45]3 years ago
7 0

Answer:

D. Both hosts 10.168.7.10 and 10.168.7.11 will be permitted

Explanation:

access-list 90

deny 10.168.7.0 0.0.0.255

permit 10.168.7.10

permit 10.168.7.11

permit 10.168.7.12

deny any

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g A smooth pipeline with a diameter of 5 cm carries glycerin at 20 degrees Celsius. The flow rate in the pipe is 0.01 m3/s. What
earnstyle [38]

Answer:

The friction factor is 0.303.

Explanation:

The flow velocity (v), measured in meters per second, is determined by the following expression:

v = \frac{4\cdot \dot V}{\pi \cdot D^{2}} (1)

Where:

\dot V - Flow rate, measured in cubic meters per second.

D - Diameter, measured in meters.

If we know that \dot V = 0.01\,\frac{m^{3}}{s} and D = 0.05\,m, then the flow velocity is:

v = \frac{4\cdot \left(0.01\,\frac{m^{3}}{s} \right)}{\pi\cdot (0.05\,m)^{2}}

v \approx 5.093\,\frac{m}{s}

The density and dinamic viscosity of the glycerin at 20 ºC are \rho = 1260\,\frac{kg}{m^{3}} and \mu = 1.5\,\frac{kg}{m\cdot s}, then the Reynolds number (Re), dimensionless, which is used to define the flow regime of the fluid, is used:

Re = \frac{\rho\cdot v \cdot D}{\mu} (2)

If we know that \rho = 1260\,\frac{kg}{m^{3}}, \mu = 1.519\,\frac{kg}{m\cdot s}, v \approx 5.093\,\frac{m}{s} and D = 0.05\,m, then the Reynolds number is:

Re = \frac{\left(1260\,\frac{kg}{m^{3}} \right)\cdot \left(5.093\,\frac{m}{s} \right)\cdot (0.05\,m)}{1.519 \frac{kg}{m\cdot s} }

Re = 211.230

A pipeline is in turbulent flow when Re > 4000, otherwise it is in laminar flow. Given that flow has a laminar regime, the friction factor (f), dimensionless, is determined by the following expression:

f = \frac{64}{Re}

If we get that  Re = 211.230, then the friction factor is:

f = \frac{64}{211.230}

f = 0.303

The friction factor is 0.303.

4 0
3 years ago
Am i eating ramon nooddles rn
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Answer:

You are eating ramen

Explanation:

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The convection heat transfer coefficient for a clothed person standing in moving air is expressed as h 5 14.8V0.69 for 0.15 , V
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Explain about Absolute viscosity, kinematic viscosity and SUS?
ArbitrLikvidat [17]

Answer:

Absolute viscosity is the evaluation of the resistance (INTERNAL) of the fluid  flow

Kinematic viscosity relates to the dynamic viscosity and density proportion.

SUS stands for Sabolt Universal Seconds. it is units which described the variation of oil viscosity

Explanation:

Absolute viscosity is the evaluation of the resistance (INTERNAL) of the fluid  flow, whereas Kinematic viscosity relates to the dynamic viscosity and density proportion. fluid with distinct kinematic viscosities may have similar dynamic viscosities and vice versa.Dynamic viscosity provides you details of  power required to make the fluid flow at some rate, however kinematic viscosity shows how quick the fluid moves when applying a certain force.

SUS stands for Sabolt Universal Seconds. it is units which described the variation of oil viscosity when change with change in temperature. it is measured by using viscosimeter.

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Most of the work that engineers do with fluids occurs in nature. True False
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True depending the jobs
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