Answer:
17.658 kPa
Explanation:
The hydrostatic pressure of a fluid is the weight of a column of that fluid divided by the base of that column.

Also, the weight of a column is its volume multiplied by it's density and the acceleration of gravity:

Meanwhile, the volume of a column is the area of the base multiplied by the height:

Replacing:

The base cancels out, so:

The pressure depends only on the height of the fluid column, the density of the fluid and the gravity.
If you have two point at different heights (or depths in the case of objects submerged in water) each point will have its own column of fluid exerting pressure on it. Since the density of the fluid and the acceleration of gravity are the same for both points (in the case of hydrostatics density is about constant for all points, it is not the case in the atmosphere), we can write:

We do not know at what depth the man of this problem is, but it doesn't matter, because we know the difference in height of the two points of interes (h1 - h2) = 1.8 m. So:

Answer:
1568N
2195.2J
Explanation:
Given parameters:
Mass of the weight = 160kg
Distance = 1.4m
Unknown:
Force applied to lift the weight = ?
Energy expended = ?
Solution:
The force applied in moving a body with a given mass through a distance is the weight;
Force applied = mg
Where m is the mass
g is the acceleration due to gravity
i. Applied force = 160 x 9.8 = 1568N
ii. The energy used to lift the weight is given as;
Energy = mgh
h is the vertical distance
Energy = 1568 x 1.4 = 2195.2J
Answer:
define the problem, do background research and specify requirements
Answer:
What force is requiere to move the cylinder along
Explanation:
The kinematic viscosity of the ol is 0.006 fr2
Answer:
E = 8.83 kips
Explanation:
First, we determine the stress on the rod:

where,
σ = stress = ?
F = Force Applied = 1300 lb
A = Cross-sectional Area of rod = 0.5
Therefore,

Now, we determine the strain:

Now, the modulus of elasticity (E) is given as:

<u>E = 8.83 kips</u>