All categories

3 years ago

1. Describe simply what will happen to an airplane in flight in the following conditions:

Engineering

1 answer:

notka56 [123]3 years ago

4 0

Answer:

For the two you haven't answered: (Drag greater than thrust, lift greater than weight) It will accelerate backwards (decelerate) and upwards

(Lift greater than weight, thrust greater than drag) accelerate upwards and forwards.

You might be interested in

Calculate the amount of current flowing through a 75-watt light bulb that is connected to a 120-volt circuit in your home.

aev [14]

Answer: 220

Explanation:

7 0

3 years ago

Explain, with reasons, whether the LTIC systems described by the following differential equations are (i) stable or unstable in

taurus [48]

Answer:

Explanation:

The LTIC system is the Linear Time Invariant Theory, also known as LTI system theory, investigates the response of a linear and time-invariant system to an arbitrary input signal.

For the step by step Solution to the question you asked, go through the attached documents.

8 0

3 years ago

A thick casting with a thermal diffusivity of 5 x 10-6 m2/s is initially at a uniform temperature of 150oC. One surface of the c

fredd [130]

Answer:

$T_o = 141.81 ^0C$

Explanation:

Given that;

Thermal diffusivity $\alpha = 5 \times 10 ^{-6} m^2/s$

Thermal conductivity $k = 20 \ W/m.K$

Heat transfer coefficient h = ( we are to assume the imposed surface temperature ) = 20 W/m².K

Initial temperature = 150 ° C = (150+273) K = 423 K

Then coolant temperature with which the casting is exposed to = 20° C = (20+273)K = 293 K

Time = 40 seconds

Length = 20mm = 0.02 m

The objective is to determine the temperature at the surface at a depth of 20 mm after 40 seconds.

$Bi = \dfrac{hL}{k}$

$Bi = \dfrac{20*0.02}{20}$

Bi == 0.02

$\tau = \dfrac{\alpha t}{L^2}$

$\tau= \dfrac{5*10^{-6 }* 40}{0.020^2}$

$\tau = 0.5$

For a wall at 0.2 Bi

$A_1 = 1.0311$

$\lambda _1 = 0.4328$

Therefore;

$\dfrac{T_o - T_{\infty}}{T_i - T_{\infty}}= A_1 e ^{-( \lambda_1^2 \ \tau)$

$\dfrac{T_o - 293 }{423 - 293}= 1.0311 \times e ^{-( 0.438^2 \times 0.5 )$

$\dfrac{T_o - 293 }{423 - 293}= 1.0311 \times e ^{-( 0.0959 )$

$\dfrac{T_o - 293 }{130}= 1.0311 \times 0.9085$

$\dfrac{T_o - 293 }{130}= 0.937$

$T_o - 293= 0.937 \times 130$

$T_o - 293= 121.81$

$T_o = 121.81+ 293$

$T_o = 414.81 \ K$

$T_o = (414.81 - 273)^0C$

$T_o = 141.81 ^0C$

4 0

4 years ago

A Carnot heat engine absorbs 235 KW of heat from a heat source and rejects 164 KW to the atmosphere. Determine the thermal effic

nevsk [136]

Answer:

43.2%

Explanation:

Given that,

Heat absorbed by a carnot heat engine, $Q_1=235\ kW$

Heat rejected to the atmosphere, $Q_2=164\ kW$

We need ti find the thermal efficiency of the heat engine. It is equal to the ratio of output work to the energy supplied. Its mathematical form is given by :

$\eta=1-\dfrac{Q_1}{Q_2}\\\\\eta=1-\dfrac{235}{164}\\\\\eta=-0.432$

$\eta=-43.2\%$

The egative value of efficiency shows work is done by the engine.

5 0

3 years ago

The average grain diameter of an aluminum alloy is 14 mu m with a strength of 185 MPa. The same alloy with an average grain diam

timama [110]

Answer:

See explanations for completed answers

Explanation:

Given that; The average grain diameter of an aluminum alloy is 14 mu m with a strength of 185 MPa. The same alloy with an average grain diameter of 50 mu m has a strength of 140 MPa. (a) Determine the constants for the Hall-Patch equation for this alloy, (b) How much more should you reduce the grain size if you desired a strength of 220 MPa

See attachment for completed solvings

6 0

3 years ago