Answer:She would need to first know the weight of the sculpture and what she is going to move it with then she will need to use newton's second law to calculate the amount of force needed to move it
Explanation: I just did the assignment on edgunity
I think number 1 is incorrect I believe that answer is D. Number 6 I believe would be B. The rest seem to be correct.
Answer:
the volume is 0.253 cm³
Explanation:
The pressure underwater is related with the pressure in the surface through Pascal's law:
P(h)= Po + ρgh
where Po= pressure at a depth h under the surface (we assume = 1atm=101325 Pa) , ρ= density of water ,g= gravity , h= depth at h meters)
replacing values
P(h)= Po + ρgh = 101325 Pa + 1025 Kg/m³ * 9.8 m/s² * 20 m = 302225 Pa
Also assuming that the bubble behaves as an ideal gas
PV=nRT
where
P= absolute pressure, V= gas volume ,n= number of moles of gas, R= ideal gas constant , T= absolute temperature
therefore assuming that the mass of the bubble is the same ( it does not absorb other bubbles, divides into smaller ones or allow significant diffusion over its surface) we have
at the surface) PoVo=nRTo
at the depth h) PV=nRT
dividing both equations
(P/Po)(V/Vo)=(T/To)
or
V=Vo*(Po/P)(T/To) = 0.80 cm³ * (101325 Pa/302225 Pa)*(277K/293K) = 0.253 cm³
V = 0.253 cm³
Answer:
-26 m/s (backward)
Explanation:
We can solve this problem by using the law of conservation of momentum.
In fact, the total momentum momentum of the cannon + ball system must be conserved before and after the explosion.
Before the explosion, they are both at rest, so the total momentum is zero:
p = 0
After the explosion, the total momentum is:
where
M = 1.5 kg is the mass of the cannon
m = 0.52 kg is the mass of the ball
v = +75 m/s is the velocity of the ball
V is the velocity of the cannon
Since the momentum is conserved, we can equate the two expressions:
And solving, we find V:
where the negative sign means the direction is opposite to that of the ball.
