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Anastaziya [24]
1 year ago
3

a truck weights 17000 N with a coefficient static friction of 0.170, what force is required to start the truck rolling

Physics
1 answer:
elena55 [62]1 year ago
8 0

Given, the weight of the truck, W=17000 N

The coefficient of static friction, μ=0.170

The frictional force is the force that opposes the motion of an object. The static frictional force acts on the objects at rest and opposes the motion of the objects.

To get the truck rolling the force applied to the truck should be more than or equal to the static frictional force acting on the truck.

The static friction is given by,

f=W\mu

On substituting the known values,

\begin{gathered} f=17000\times0.17 \\ =2890\text{ N} \end{gathered}

Therefore the force required to start the truck rolling is 2890 N

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You have a stopped pipe of adjustable length close to a taut 62.0 cmcm, 7.25 gg wire under a tension of 4710 NN. You want to adj
Oksana_A [137]

Answer:

6 cm long

Explanation:

F = 4110N

Vo(speed of sound) = 344m/s

Mass = 7.25g = 0.00725kg

L = 62.0cm = 0.62m

Speed of a wave in string is

V = √(F / μ)

V = speed of the wave

F = force of tension acting on the string

μ = mass per unit density

F(n) = n (v / 2L)

L = string length

μ = mass / length

μ = 0.00725 / 0.62

μ = 0.0116 ≅ 0.0117kg/m

V = √(F / μ)

V = √(4110 / 0.0117)

v = 592.69m/s

Second overtone n = 3 since it's the third harmonic

F(n) = n * (v / 2L)

F₃ = 3 * [592.69 / (2 * 0.62)

F₃ = 1778.07 / 1.24 = 1433.927Hz

The frequency for standing wave in a stopped pipe

f = n (v / 4L)

Since it's the first fundamental, n = 1

1433.93 = 344 / 4L

4L = 344 / 1433.93

4L = 0.2399

L = 0.0599

L = 0.06cm

L = 6cm

The pipe should be 6 cm long

6 0
3 years ago
A force of 20 N acts on a 4 kg cart for 10 s . How far will it go (using the second law) ?
Elden [556K]
This took me a short while to figure out, but I am still not entirely sure if this is correct, this is just from my basic understanding of Newtons Second Law of Motion.

You have a 4kg cart with a force of 20N acting on it.

The formula for working out the acceleration is.
a=Fnet÷mass

Substitute in the information.
a=20N÷4kg

Now you solve it to give you.
a=5m/s

So now what you should be able to do is figure out that after 10 seconds the cart travelling at 5m/s would have travelled 10 metres.

This is achieved by finding out how many 5's go into 10 which is 2.
So you do 5×2 which equals 10.

The 4kg cart has travelled 10 meters in 10 seconds with a force of 20N acting upon it.

I hope that this has helped you.
8 0
3 years ago
Placement.
stealth61 [152]

Answer:

kinetic energy will be equal to 0

Explanation:

this is because at final position velocity of body will become zero.

kinetic energy eill be 8 times

7 0
3 years ago
If a beam of red light and a beam of violet light are incident at the same angle on the inclined surface of a prism from air med
Kaylis [27]

Answer:  The red light bends the least while the violet the most.

Explanation:

i think this is it

3 0
3 years ago
A quantity of a gas has an absolute pressure of 400 kPa and an absolute temperature of 110 degrees kelvin. When the temperature
shepuryov [24]

You can make sure there's no change in volume by keeping
your gas in a sealed jar with no leaks.  Then you can play with
the temperature and the pressure all you want, and you'll know
that the volume is constant.

For 'ideal' gases,

       (pressure) times (volume) is proportional to (temperature).

And if volume is constant, then

                 (pressure) is proportional to (temperature) .

So if you increase the temperature from 110K to 235K,
the pressure increases to  (235/110)  of where it started.

     (400 kPa) x (235/110)  =  854.55 kPa. (rounded)

Obviously, choice-b is the right one, but
I don't know where the .46 came from.
 
4 0
3 years ago
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