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Artemon [7]
1 year ago
10

IM A plastic sphere floats in water with 50.0% of its volume submerged. This same sphere floats in glycerin with 40.0 \% of its

volume submerged. Determine the densities of(b) the
Physics
1 answer:
arsen [322]1 year ago
6 0

Density of glycerin is 5/4 times water density.

Density of the sphere is 1/2 times water density.

<h3>How to find the density of sphere floats and glycerin?</h3>

Density is defined as the ratio of mass to volume, that is density is the amount of mass per unit of volume.

A substance's density exist defined as its mass per unit of volume. Density is most frequently represented by the symbol, however Latin letter D may also be utilized. If the mass or volume of an object is altered, the density of the thing may also change. Water, for example, has a specific density. An object will sink if its density exists greater than that of water; it will float if its density is lower.

Since a plastic sphere floats in water with 50% of its volume submerged.

So, the Density of the sphere = 1/2× water density

Since the same sphere floats in glycerin with 40% of its volume submerged.

So, the Density of the sphere = 4/100 × Glycerin density

= 2/5 × Glycerin density

Density of Glycerin = 5/2 of sphere density

Density of glycerin = 5/2 × 1/2 × water density

Density of glycerin = 5/4 × water density

To learn more about the volume of sphere floats refer to:

brainly.com/question/10827296

#SPJ4

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Andrew [12]

Answer:

2Ω

Explanation:

If a 18Ω resistance is cut into three equal parts each of the resistance will be 18Ω/3 = 6Ω

Equivalent ratio in parallel is expressed as:

1/R = 1/6 + 1/6 + 1/6

1/R = 3/6

Cross multiply

3R = 6

R = 6/3

R = 2Ω

Hence the required equivalent resistance is 2Ω

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3 years ago
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Answer:

This question is asking to identify the following variables:

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Explanation:

Independent variable in an experiment is the variable that is manipulated or changed by the experimenter in order to effect a measurable outcome. In this case, the independent variable is the TYPE OF SOIL used.

Dependent variable is the measurable variable that responds to changes made to the independent variable. In this experiment, the dependent variable is the HEIGHT AND NUMBER OF LEAVES of each rose.

Constants or control variable is the variable that is kept unchanged or constant for all groups throughout the experiment. In this experiment, the constants are SAME ROSE PLANT, SAME TIME INTERVAL (1 WEEK).

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If the electron just misses the upper plate as it emerges from the field, find the magnitude of the electric field.
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Answer:

The magnitude of the electric field be 171.76 N/C so that the electron misses the plate.

Explanation:

As data is incomplete here, so by seeing the complete question from the search the data is

vx_0=1.1 x 10^6

ax=0 As acceleration is zero in the horizontal axis so

Equation of motion in horizontal direction is given as

s_x=v_x_0 t

t=\frac{s_x}{v_x}\\t=\frac{2 \times 10^{-2}}{1.1 \times 6}\\t=1.82 \times 10^{-8} s

Now for the vertical distance

vy_o=0

than the equation of motion becomes

s_y=v_y_0 t+\frac{1}{2} at^2\\s_y=\frac{1}{2} at^2\\0.5 \times 10^{-2}=\frac{1}{2} a(1.82 \times 10^{-8})^2\\a=3.02 \times 10^{13} m/s^2

Now using this acceleration the value of electric field is calculated as

E=\frac{F}{q}\\E=\frac{ma}{q}\\E=\frac{m_ea}{q_e}\\

Here a is calculated above, m is the mass of electron while q is the charge of electron, substituting values in the equation

E=\frac{9.1\times 10^{-31} \times 3.02 \times 10^{13} }{1.6 \times 10^{-19}}\\E=171.76 N/C

So the magnitude of the electric field be 171.76 N/C so that the electron misses the plate.

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