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Artemon [7]
1 year ago
10

IM A plastic sphere floats in water with 50.0% of its volume submerged. This same sphere floats in glycerin with 40.0 \% of its

volume submerged. Determine the densities of(b) the
Physics
1 answer:
arsen [322]1 year ago
6 0

Density of glycerin is 5/4 times water density.

Density of the sphere is 1/2 times water density.

<h3>How to find the density of sphere floats and glycerin?</h3>

Density is defined as the ratio of mass to volume, that is density is the amount of mass per unit of volume.

A substance's density exist defined as its mass per unit of volume. Density is most frequently represented by the symbol, however Latin letter D may also be utilized. If the mass or volume of an object is altered, the density of the thing may also change. Water, for example, has a specific density. An object will sink if its density exists greater than that of water; it will float if its density is lower.

Since a plastic sphere floats in water with 50% of its volume submerged.

So, the Density of the sphere = 1/2× water density

Since the same sphere floats in glycerin with 40% of its volume submerged.

So, the Density of the sphere = 4/100 × Glycerin density

= 2/5 × Glycerin density

Density of Glycerin = 5/2 of sphere density

Density of glycerin = 5/2 × 1/2 × water density

Density of glycerin = 5/4 × water density

To learn more about the volume of sphere floats refer to:

brainly.com/question/10827296

#SPJ4

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givi [52]

Initial velocity = Vo= 25 m/s

Final velocity = V = x

Acceleration= a = 6 m/s^2

time= t = 4 seconds

Appy the equation:

V = Vo + at

Replacing:

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8 0
1 year ago
A single-phase electrical load draws 600KVA at 0.6 power factor lagging. a) Find the real and reactive power absorbed by the loa
Whitepunk [10]

Answer:

(a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

Explanation:

Given that,

Power factor = 0.6

Power = 600 kVA

(a). We need to calculate the reactive power

Using formula of reactive power

Q=P\tan\phi...(I)

We need to calculate the \phi

Using formula of \phi

\phi=\cos^{-1}(Power\ factor)

Put the value into the formula

\phi=\cos^{-1}(0.6)

\phi=53.13^{\circ}

Put the value of Φ in equation (I)

Q=600\tan(53.13)

Q=799.99\ kVAR

(b). We draw the power triangle

(c). We need to calculate the reactive power of a capacitor to be connected across the load to raise the power factor to 0.95

Using formula of reactive power

Q'=600\tan(0.95)

Q'=9.94\ KVAR

We need to calculate the difference between Q and Q'

Q''=Q-Q'

Put the value into the formula

Q''=799.99-9.94

Q''=790.05\ KVAR

Hence, (a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

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4 years ago
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Answer:

See below.

Explanation:

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