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kompoz [17]
1 year ago
8

What type of metamorphism involves chemical reactions between oceanic lithosphere and warm fluids near mid-ocean ridges?.

Chemistry
1 answer:
Mariulka [41]1 year ago
3 0

Hydrothermal metamorphism involves chemical reactions between oceanic lithosphere and warm fluids near mid-ocean ridges

Hydrothermal metamorphism is most common along mid-ocean ridge spreading centers, where warm seawater percolates through hot, cracked basalt. Metamorphism of basalt occurs as a result of chemical interactions between hot saltwater and basalt. On continents, crustal rocks can be metamorphosed by invading, hot fluids associated with igneous intrusions, resulting in hydrothermal metamorphism.

The interaction of a rock with a high-temperature fluid of changing composition results in hydrothermal metamorphism. The compositional mismatch between an existing rock and the entering fluid causes a series of metamorphic and metasomatic processes.

Hydrothermal metamorphism changes Mg-Fe-rich hydrous minerals like talc, chlorite, serpentine, actinolite, tremolite, zeolites, and clay minerals. Hydrothermal metamorphism is frequently responsible for the formation of rich ore deposits.

For more information on hydrothermal metamorphism, visit :

brainly.com/question/8344791

#SPJ4

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Which option is an example of a chemical property? Question options: reactivity color melting point density
White raven [17]

Hi there, the correct answer to this would be reactivity because color, melting point, and density are all examples of physical properties.

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3 years ago
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How many atoms are in the following compound? 5Fe2(CO3)3 *
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Answer:

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3 years ago
How many grams of aluminum are required to react with 35 mL of 2.0 M hydrochloric acid, HCl?__ HCl + __ Al --> __ AlCl3 + __
kiruha [24]

Answer:

0.6258 g

Explanation:

To determine the number grams of aluminum in the above reaction;

  • determine the number of moles of HCl
  • determine the mole ratio,
  • use the mole ratio to calculate the number of moles of aluminum.
  • use RFM of Aluminum to determine the grams required.

<u>Moles </u><u>of </u><u>HCl</u>

35 mL of 2.0 M HCl

2 moles of HCl is contained in 1000 mL

x moles of HCl is contained in 35 mL

x \: mol \:  =  \:  \frac{2 \:  \times  \: 35}{1000}  \\  = 0.07 \: moles \:

We have 0.07 moles of HCl.

<u>Mole </u><u>ratio</u>

  • Balanced equation

6HCl(aq) + 2Al(s) --> 2AlCl3(aq) + 3H2(g)

Hence mole ratio = 6 : 2 (HCl : Al

  • but moles of HCl is 0.07, therefore the moles of Al;

=  \frac{2}{6}  \times 0.07 \\  \:  = 0.0233333 \: moles

Therefore we have 0.0233333 moles of aluminum.

<u>Grams of </u><u>Aluminum</u>

We use the formula;

grams \:  = moles \:  \times  \: rfm

The RFM (Relative formula mass) of aluminum is 26.982g/mol.

Substitute values into the formula;

= 0.0233333 \: moles  \:  \times  \: 26.982 \:  \frac{g}{mol}  \\  = 0.625799 \: grams

The number of grams of aluminum required to react with HCl is 0.6258 g.

3 0
2 years ago
An 80.0-gram sample of water at 10.0°C absorbs 1680 Joules of heat energy. What is the final temperature of the water? a 50.0°C
ICE Princess25 [194]

Answer:

b)15.0°C

Explanation:

Specific Heat of Water=4.2 J/g°C

This means, that 1 g of Water will take 4.2 J of energy to increase its temperature by 1°C.

∴80 g Water will take 80×4.2 J of energy to increase its temperature by 1°C.

80×4.2 J=336 J

Total Energy Provided=1680 J

The temperature increase=\frac{\textrm{Total energy required}}{\textrm{energy required to increase temperature by one degree}}

Temperature increase=\frac{1680}{336}

=5°C

Initial Temperature =10°C

Final Temperature=Initial + Increase in Temperature

=10+5=15°C

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