Valence must be considered and whether the substance is an atom or molecule, for example: 2Na + Cl2=>2 NaCl
Answer:
D. Homogeneous;Heterogeneous.
Explanation:
Homogeneous equilibrium refers to a reaction in which the reactants and products are in the same phase i.e whether gaseous or liquid. This means it's concentration reactants and products in a chemical reaction can vary over a wide range.
For example,
The Heterogeneous equilibrium refers to a reaction in which the reactants and products are in different phases i.e solid, gaseous, liquid or aqueous. Its position isn't dependent on the amounts of pure liquids or solids present in the reaction.
For example,
Answer:
0.16 J/g℃
Explanation:
We have the following data:
heat = 1,200 J
mass of metal = m = 150 g
change in temperature = ΔT = 50.0℃
The heat absorbed is calculated by using the following equation:
heat = m x Cp x ΔT
So, we introduce the data in the equation to calculate the specific heat of the metal (Cp), as follows:
Cp = heat/(m x ΔT) = (1,200 J)/(150 g x 50.0℃) = 0.16 J/g℃
Br is a non-metal. The other answers like Os, Ir, W are not combinations while Sr is a metal. So Br is your answer.
<h3 /><h3>Further explanation</h3>
Given
Element K : 12 protons, 24 neutrons
Element L : 17 protons, 36 neutrons
Required
the number of protons, neutrons and electrons possessed by the ions of the two elements.
Solution
number of protons=atomic number = 12
electron configuration : 1s² 2s² 2p⁶ 3s²
The element will release 2 electrons to make it stable, thus forming a cation with a +2 charge
number of protons = 12
number of electrons = 10
number of neutrons = 24
number of protons=atomic number = 17
electron configuration : 1s² 2s² 2p⁶ 3s²3p⁵
The element will gain 1 electrons to make it stable, thus forming a anionwith a -1 charge
number of protons = 17
number of electrons = 18
number of neutrons = 36
<em>If we look at this problem, it looks like the numbers 24 and 36 are mass numbers, not the number of neutrons, so the possible elements are Mg and Cl, and the ions are Mg²⁺ and Cl⁻</em>