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Grace [21]
1 year ago
8

When an electron drops from a higher energy level to a lower one, energy is emitted. in comparison, how much energy is required

to reverse the process, going from the lower level to the higher level?
Chemistry
1 answer:
NNADVOKAT [17]1 year ago
7 0

Energy is released when an electron transitions from one energy level to another. In contrast, the same amount of energy is needed to carry out the process, the other way around, from the bottom elevation to the upper one.

What occurs when an electron transitions from one energy level to another?

  • The energy of the electron drops when it changes levels, and the atom releases photons. The electron emits a photon when it transitions from a greater to a lower energy level. The energy emitted is precisely the energy that is lost when an electron moves to a level with less energy.
  • An atom's electrons have negative energy. The electron must be given energy in order to be removed from the hydrogen atom, as shown by the negative sign. The quantity of energy in the atom will rise by supplying the electron with energy. Similar to how a ball on Earth chooses to rest in valleys rather than hills, the electron wants to spend the majority of its time at a lower energy level.
  • For a brief period of time, the electron remains in an excited state. The energy required to bring the electron to its lower-energy state will be released when the electron transitions between excited and unexcited states.

Learn more about electrons here:

brainly.com/question/1255220

#SPJ4

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3 years ago
How many sulfur atoms are in 0.45 mol BaSO4??
Lemur [1.5K]

(0.45 mol BaSO_{4})*(\frac{6.022*10^23 molecules}{mol})*(\frac{1 atom S}{1 molecule BaSO_{4}}) = 2.7*10^{23}

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Which BEST describes the difference between speed and velocity? A) Velocity is instantaneous.
aleksandrvk [35]

Answer:

Option D describe the best this statement .

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3 0
4 years ago
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1) Humans have how many sets of teeth?
Verizon [17]
<span>1) Humans have how many sets of teeth?

C) 4

2) Adults have how may permanent teeth?

B) 32

3) What type of food products make teeth stronger?

Cheese and Yogurt

4) What is the visible part of the tooth?

C) crown



5) What part of the tooth is harder than bone?

D) dentin


6) What part of the tooth is soft and contains the nerves?
A) pulp


7) What refers to the alignment of the teeth?
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Occlusion</span><span>

8) The lower teeth protect what?

D) tongue


9) Malocclusion is the least common reason for referral to orthodontists.

False



10) Usually, malocclusion is hereditary.
True


11) Which type of malocclusion is commonly referred to as an overbite?

Class Two

12) Bacteria are living organisms than cause cavities.
True




13) What is the whitish film that grows on your teeth called?

Plaque 

14) What is the best fighter of cavities?

Fluoride

Gingivitis is the inflammation of the
A) gums



16) Gingivitis is permanent.

False


17) Name 2 ways to fight gingivitis.

Proper Toothbrushing and Flossing
</span>Professional Dental Cleanings<span>

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B) bacteria



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6 0
3 years ago
Mercury’s atomic emission spectrum is shown below. Estimate the wavelength of the orange line. What is its frequency? What is th
lions [1.4K]

The wavelength of the orange line is 610 nm, the frequency of this emission is 4.92 x 10¹⁴ Hz and the energy of the emitted photon corresponding to this <em>orange line</em> is 3.26 x 10⁻¹⁹ J.

<em>"Your question is not complete, it seems to be missing the diagram of the emission spectrum"</em>

the diagram of the emission spectrum has been added.

<em>From the given</em><em> chart;</em>

The wavelength of the atomic emission corresponding to the orange line is 610 nm = 610 x 10⁻⁹ m

The frequency of this emission is calculated as follows;

c = fλ

where;

  • <em>c is the speed of light = 3 x 10⁸ m/s</em>
  • <em>f is the frequency of the wave</em>
  • <em>λ is the wavelength</em>

f = \frac{c}{\lambda } \\\\f = \frac{3\times 10^8}{610 \times 10^{-9}} \\\\f = 4.92 \times 10^{14} \ Hz

The energy of the emitted photon corresponding to the orange line is calculated as follows;

E = hf

where;

  • <em>h is Planck's constant = 6.626 x 10⁻³⁴ Js</em>

<em />

E = (6.626 x 10⁻³⁴) x (4.92 x 10¹⁴)

E = 3.26 x 10⁻¹⁹ J.

Thus, the wavelength of the orange line is 610 nm, the frequency of this emission is 4.92 x 10¹⁴ Hz and the energy of the emitted photon corresponding to this <em>orange line</em> is 3.26 x 10⁻¹⁹ J.

Learn more here:brainly.com/question/15962928

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