C. allow ions to flow through the water
KBr(s) = K⁺(aq) + Br⁻(aq)
Explanation:
You have a solution that contains 36 g HCl dissolved in 64 g water
Molar mass HCl = 36.45 g/mol
Mol HCl in 36 g = 36 g / 36.45 g/mol = 0.9876 mol
Molar mass H2O = 18 g/mol
Mol H2O in 64 g = 64 g / 18 g/mol = 3.5556 mol
Total mol = 0.9875 + 3.5556 = 4.5431 mol
Mol fraction HCl = 0.9876 mol / 4.5431 mol = 0.2174
Mol fraction H2O = 3.5556 / 4.5431 = 0.7826
The answer should have 2 significant digits:
Mol fraction HCl = 0.22
Mol fraction H2O = 0.78
Mol fraction has no units.
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Answer:
The war of the currents, sometimes called battle of the currents, was a series of events surrounding the introduction of competing electric power transmission systems in the late 1880s and early 1890s.
Explanation: