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3 years ago

Deffinition of density

Chemistry

2 answers:

Ratling [72]3 years ago

6 0

Answer:

Density is a measure of mass per volume. The average density of an object equals its total mass divided by its total volume. An object made from a comparatively dense material (such as iron) will have less volume than an object of equal mass made from some less dense substance (such as water).

Explanation:

Bas_tet [7]3 years ago

4 0

Solidity, solidness, denseness, thickness, substance, mass......

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If a given aqueous solution at 298 K contains [H+] = 1.0 × 10-9, what is the [OH-]?

Zinaida [17]

Answer:

Explanation:

$\frac{1x10}x^{-14} = 1x10^{-9} \\ x =1x10^{-5} \\\\[OH][H]= 1x10^{-14}$

The concetration can be found by dividing the water ph constant by the [H=] or [OH] to find the other

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3 years ago

In a separate experiment beginning from the same initial conditions, including a temperature Ti of 25.0°C, half the number of mo

NNADVOKAT [17]

Answer:

- 178 ºC

Explanation:

The ideal gas law states that :

PV = nRT,

where P is the pressure, V is the volume, n is number of moles , R is the gas constant and T is the absolute temperature.

For the initial conditions :

P₁ V₁ = n₁ R T₁ (1)

and for the final conditions:

P₂V₂= n₂ R T₂ where n₂ = n₁/2 then P₂ V₂ = n₁/2 T₂ (2)

Assuming V₂ = V₁ and dividing (2) by Eqn (1) :

P₂ V₂ = n₁/2 R T₂ / ( n₁ R T₁) then P₂ / P₁ = 1/2 T₂ / T₁

4.10 atm / 25.7 atm = 1/2 T₂ / 298 K ⇒ T₂ = 0.16 x 298 x 2 = 95.1 K

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3 years ago

A sample of gas with an initial volume of 28.4 Liters at a pressure of 725 mmHg and a temperature of 305 K is compressed to a vo

Lerok [7]

Answer:

The final pressure is 2.25 atm or 1710 mm Hg

Explanation:

Step 1: Data given

The initial volume = 28.4 L

The initial pressure = 725 mm Hg ( = 725/760 atm) = 0.953947 atm

The initial temperature = 305 K

The new volume is 14.8 L

The new temperature = 375 K

Step 2: Calculate the new pressure

(P1*V1)/T1 = (P2*V2)/T2

⇒ with P1 = the initial pressure = 725 mmHg = 0.953947 atm

⇒ with V1 = the initial volume = 28.4 L

⇒ with T1 = The initial temperature = 305 K

⇒ with P2 = the new pressure = TO BE DETERMINED

⇒ with V2 = the new volume = 14.8 L

⇒ with T2 = the new temperature = 375 K

(0.953947 * 28.4)/305 = (P2 * 14.8)/375

P2 = 2.25 atm = 1710 mm Hg

The final pressure is 2.25 atm or 1710 mm Hg

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Explanation:

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