The restoring force of the spring cancels the weight of the mass, so by Newton's second law
∑ F = F[spring] - mg = 0 ⇒ F[spring] ≈ 45.1 N
where m = 4.60 kg and g = 9.80 m/s². Then the spring constant is k such that by Hooke's law,
F[spring] = k x
where x = 0.0231 m. Then the spring constant is
k = F[spring]/x ≈ 1950 N/m
Answer:

Explanation:
For a charged particle moving perpendicularly to a magnetic field, the magnitude of the force exerted on the particle is:

where
q is the magnitude of the charge of the particle
v is the velocity of the particle
B is the magnetic field strength
In this problem, we have
is the charge of the electron
is the velocity
is the magnetic field
Substituting into the formula, we find the force:

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140 Jules. Is the correct answer