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3 years ago

Complete the sentences to describe the convection experiment.

Physics

2 answers:

rodikova [14]3 years ago

6 0

Answer: red water in hot water

Rose to the top of the beaker

Warmer than

Explanation:

riadik2000 [5.3K]3 years ago

4 0

Answer:

The heat transfer model showed convection.

In the convection model, the red water on the bottom of the beaker is hot

This means that the water at the bottom of the beaker was less dense than the water near the top of the beaker.

Explanation:

Convection is the transference of heat energy by the movement (translation) of the particles of fluid (liquids or gases).

When the water on the bottom of the beaker is heated, it expands and becomes less dense.

The water near the top of the beaker is cold which makes it denser than the water at the bottom of the beaker.

Thus, the hot water from the bottom of the beaker will ascend toward the top of the beaker, while the cold water on top will descend toward the bottom. As long, as there is a difference of temperature between the water on the bottom and on top of the beaker, there will be a continuous movement of the particles: cold particles from the top replace hot particles from the bottom that ascend, and when the cold particles are heated they will ascend and will be replaced by new cold particles. This continuous translation of hot and cold particles in fluids is the model of heat transfer by convection.

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A 0.157-kg baseball moving at 21.2 m/s strikes the glove of a catcher. The glove recoils a distance of 10.7 cm.The magnitude of

san4es73 [151]

Answer:329.72 N

Explanation:

Given

mass of ball $m=0.157\ kg$

velocity of ball $v=21.2\ m/s$

glove recoil distance $d=10.7\ cm$

Energy associated with ball E=kinetic energy of ball

$E=\frac{1}{2}mv^2$

$E=\frac{1}{2}\times 0.157\times 21.2^2$

$E=35.28\ J$

Now if an average for is applied to stop the ball then work done by this force is equal to kinetic energy of the ball

$W=F_{avg}\cdot d=E$

$F_{avg}=\frac{E}{d}=\frac{35.28}{0.107}=329.72\ N$

6 0

3 years ago

Read 2 more answers

A constant electric field of 5.00 N/C points along the positive x-direction. An electron, initially at rest, moves a distance of

Genrish500 [490]

Answer:

1.875 x 10⁶ m /s .

Explanation:

Force on electron = E e where E is electric field and e is charge on electron

acceleration generated = Ee / m where m is mass of the electron .

Putting the values

acceleration generated = 5 x 1.6 x 10⁻¹⁹ / 9.1 x 10⁻³¹

= .879 x 10¹² m /s²

v² = u² + 2 as , initial velocity u = 0 , displacement s = 2 m

v² = 0 + 2 x .879 x 10¹² x 2

v = 1.875 x 10⁶ m /s .

7 0

2 years ago

A uniform metal meter-stick is balanced with a 1.0 kg rock attached to the left end of the stick. If the support is located 0.25

Dafna1 [17]

Answer:

c) 1.0 kg

Explanation:

The mass of the stick will be located at the centre of the metre rule. Since the rock is located 0.25m from the pivot, the mass of the meter rule is also 0.25m to the Right of the support

According to law of moment

Sum of clockwise moment = sum of anti clockwise moments

Clockwise moment = M×0.25(mass of metre rule is M)

CW moment = 0.25M

Anti clockwise moment = 0.25×1

ACW moments = 0.25kgm

Equate;

0.25M = 0.25

M = 0.25/0.25

M = 1.0kg

Hence the mass of the metre rule is 1.0kg

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2 years ago

The Sun does NOT rotate the way Earth does. Which statement best describes the difference in their rotations?

Phantasy [73]

I believe the answer is A. Have a blessed day.

6 0

2 years ago

A ball is dropped from rest on a cliff what is the speed of the ball 5 seconds later

diamong [38]

Answer:

The velocity of the ball after 5 seconds will be 49 m/s

Explanation:

v = final velocity

u = initial velocity

g = acceleration due to gravity

t = time

Initial velocity of the ball = 0 (As the ball is dropped from rest )

Acceleration due to gravity = 9.8 m/s

Time taken = 5 sec

As the acceleration due to gravity is constant in both the cases we can use the equations of motion in order to solve this question

Part I :- As we already know the values of u,g,ant t we can use the first equation of motion in order to find v

Part II :- As we know the values of u, t , g we can use the second equation of motion in order to find s.

Velocity of the ball after 5 seconds

Distance covered by the ball in 5 sec

4 0

2 years ago