Hello.
The answer is <span>remains the same.
</span>The total amount of energy stays the same because the 1st Law of Thermodynamics states that energy can neither be created nor destroyed, it can only change forms. <span>So the chemical energy is just being converted into heat and light.
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Have a nice day
Answer:
For example, when a car travels at a constant speed, the driving force from the engine is balanced by resistive forces such as air resistance and friction in the car's moving parts. The resultant force on the car is zero.
Explanation:
hope this helps
Answer:
a) 8.61 m/s, b) 5.73 m
Explanation:
a) During the collision, momentum is conserved.
mv = (m + M) V
(12.5 g) (86.4 m/s) = (12.5 g + 113 g) V
V = 8.61 m/s
b) After the collision, energy is conserved.
Kinetic energy = Work done by friction
1/2 (m + M) V² = F d
1/2 (m + M) V² = N μk d
1/2 (m + M) V² = (m + M) g μk d
1/2 V² = g μk d
d = V² / (2g μk)
d = (8.61 m/s)² / (2 × 9.8 m/s² × 0.659)
d = 5.73 m
Notice we used the kinetic coefficient of friction. That's the friction when an object is moving. The static coefficient of friction is the friction on a stationary object. Since the bullet/block combination is sliding across the surface, we use the kinetic coefficient.
I racked my brain for almost 10 minutes, until suddenly,
it hit me !
You're breathing one right now ! So am I .
Air is a mixture of a lot of elements.
Nitrogen, Oxygen, and Argon account for 99.964 percent.
The other 0.036 percent is mainly Neon, Helium, Krypton,
and Hydrogen ... more elements.
Then there are Carbon Dioxide and water vapor.
Yes, those are compounds. But together, they add up
to very little of the air we breathe, and if both of them
suddenly disappeared, we would hardly notice it.
The force exerted on the cart 2 during the collision is 2 N.
The given parameters:
- <em>Mass of cart 1 = m1 = 1 kg</em>
- <em>Mass of cart 2 = m2 = 2kg</em>
- <em>Force applied on cart 1 = 2 N</em>
According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart 1 is equal in magnitude to the force exerted on cart 2 but in opposite direction.
Thus, the force exerted on the cart 2 during the collision is 2 N.
Learn more about Newton's third law of motion here: brainly.com/question/13874955
