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Maru [420]
4 years ago
6

Which statement best describes how a wave would move differently through a pot of boiling water than the steam created from it?

Physics
2 answers:
Marina86 [1]4 years ago
3 0
<span>The wave would move faster through the water than through the steam.</span>
shepuryov [24]4 years ago
3 0

Hello. This question is incomplete. The complete question is:

"Which statement best describes how a wave would move differently through a pot of boiling water than the steam created from it? The wave would move faster through the water than through the steam. The wave would move slower through the water than through the steam. The wave would move the same speed through the water and the steam. The wave would move through the water and steam at the same speed, but decrease in speed at the transition point. "

Answer:

The wave would move faster through the water than through the steam.

Explanation:

As we already know, the water molecules at the moment when the water is boiling move very fast, due to the thermal energy that acts on them. This movement causes the mileculas to collide with each other quickly, for this reason we can observe that movement of the boiling water. This makes the wave movement in the boiling water fast.

On the other hand, all this movement is not seen in water vapor molecules, since the space between them is larger and there is no energy acting directly on them. For this reason, we can say that, through steam, the wave would not move with such speed.

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I think it's D. Usually, to find the volume of an irregularly shaped object, you put it in water with a labeled beaker to measure how much the water rises. The balance would be used to measure the mass in grams.
4 0
3 years ago
1.A little girl kicks a soccer ball. It goes 10 feet and comes back to her. How is this possible?
marishachu [46]
Something stopped the force and was able to recreate the same amount of force to send it back to her. Example: A pole
6 0
3 years ago
Read 2 more answers
A 0.046 kg golf ball hit by a driver can accelerate from rest to 67 m/s in 1 ms while the driver is in contact with the ball. Ho
Flauer [41]

Answer:

Average force = 67 mn

Explanation:

Given:

Initial velocity u = 0 m/s

Final velocity v = 67 m/s

Time t = 1 ms = 0.001 sec.

Computation:

Using Momentum theory

Change in momentum  = F × Δt

 (v-u)/t =  F × Δt

F × 0.001 = (67 - 0)/0.001

F= 67,000,000

Average force = 67 mn

3 0
3 years ago
A car accelerates from rest at 1.0 m/s2 for 20.0 second along a straight road. It then moves at a constant speed for half an hou
Whitepunk [10]

Total distance = 36500 m

The average velocity = 19.73 m/s

<h3>Further explanation</h3>

Given

vo=initial velocity=0(from rest)

a=acceleration= 1 m/s²

t₁ = 20 s

t₂ = 0.5 hr = 1800 s

t₃= 30 s

Required

Total distance

Solution

State 1 : acceleration

\tt d=vo.t+\dfrac{1}{2}at^2\\\\d=\dfrac{1}{2}\times 1\times 20^2\rightarrow vo=0\\\\d=200~m

\tt vt=vo+at\\\\vt=at\rightarrow vo=0\\\\vt=1\times 20\\\\vt=20~m/s

State 2 : constant speed

\tt d=v\times t\\\\d=20\times 1800\\\\d=36000~m

State 3 : deceleration

\tt vt=vo+at\rightarrow vt=0(stop)\\\\vo=-at\\\\20=-a.30~s\\\\a=-\dfrac{2}{3}m/s^2(negative=deceleration)

\tt d=vot+\dfrac{1}{2}at^2\\\\d=20.30-\dfrac{1}{2}.\dfrac{2}{3}.30^2\\\\d=300~m

Total distance : state 1+ state 2+state 3

\tt 200 + 36000 + 300=36500~m

the average velocity = total distance : total time

\tt avg~velocity=\dfrac{36500}{20~s+1800~s+30~s}=19.73~m/s

4 0
3 years ago
A ball is thrown upward at a 45° angle. Inthe absence of air resistance, the ballfollows aA. tangential curve.B. sine curve.C. p
Evgesh-ka [11]

As ball is projected up in air at an angle of 45 degree without any air resistance

Let the initial speed will be v

now we will have

In x direction

v_x = v cos45

in y direction

v_y = vsin45

now displacement in x direction

x = (vcos45)t + 0

displacement in y direction

y = (vsin45)t - \frac{1}{2}gt^2

now from above two equations we have

y = (vsin45)\frac{x}{vcos45} - \frac{1}{2}g(\frac{x}{vcos45})^2

y = xtan45 - \frac{1}{2v^2cos^245}gx^2

so above equation is a quadratic equation and hence it will be a parabolic curve

so correct answer will be

<em>C. parabolic curve.</em>

8 0
3 years ago
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