Answer:
a) L= 3568 m
b) 9×10^{-5} sec
c) 8.92×10^{-5} sec
Explanation:
runway length on the Earth L_o = 3600 m
Speed of the spacecraft flying past v= 4.00×10^7 m/s
then Einstein's length contraction theory,
Solving we get L= 3568 m
b) Time interval for an observer on earth when the spacecraft is directly over one end of the runway until it is directly over the other end.
L_o= 3600 m
speed v= 4.00×10^7 m/s
Then time interval Δt = L_o/v= 
= 9×10^{-5} sec
c) for the pilot the time interval will be
Δt_o = L/v = 
= 8.92×10^{-5} sec
Wavelength = speed / frequency.
Wavelength = 3x10^8 m/s / 30 hz
Wavelength = 10 million meters
1/2 wavelength = 5 million meters
(that's about 3,100 miles)
I'm pretty sure the frequency is wrong in the question.
I think it's actually 30 kHz, not 30 Hz.
That makes the antenna about 3.1 miles long.
We need to calculate speed , so we don't need to consider direction.
speed =distance/time
=(80+60)/2
=70.
But if we were to calculate velocity,we would need to consider the direction.
The direction of resultant displacement would be in north east direction with displacement
=√60^2 +80^2
=100km
The average velocity=100/2=50kmph
Covalent bonds form when electrons are shared between atoms and are attracted by the nuclei of both atoms. In pure covalent bonds, the electrons are shared equally. In polar covalent bonds, the electrons are shared unequally, as one atom exerts a stronger force of attraction on the electrons than the other.
Answer:
The velocity of the rocket is 7.8 m/s
Explanation:
