The formula we're gonna use for this problem is written below:
ΔG°= nFE°
where
n is number of mol electrons displaced in the reaction
F is Faraday's constant = 96,500 C/mol e
E° is the standard emf
ΔG° = (2)(96,500)(1.46) = <em>281,780 Joules</em>
<span>(P1/T1) = (P2/T2)
T must be in kelvin first!</span>
A) cesium chloride
B) barium oxide
C) potassium sulfide
D) beryllium chloride
E) hydrogen bromide
F) aluminum fluoride
Answer:

Explanation:
Hello there!
Unfortunately, the question is not given in the question; however, it is possible for us to compute the equilibrium constant as the problem is providing the concentrations at equilibrium. Thus, we first set up the equilibrium expression as products/reactants:
![K=\frac{[NO_2]^2}{[NO]^2[O_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BNO_2%5D%5E2%7D%7B%5BNO%5D%5E2%5BO_2%5D%7D)
Then, we plug in the concentrations at equilibrium to obtain the equilibrium constant as follows:

In addition, we can infer this is a reaction that predominantly tends to the product (NO2) as K>>>>1.
Best regards!