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3 years ago

Which choice describes a community?

Chemistry

2 answers:

kompoz [17]3 years ago

7 0

All of the populations of organism living and interaction in a particular area make up a biological community.

It means species make a population, and pollution make biological community

Species ------ > population ------- .>community

hence the correct answer is B.

a forest of birds, insects, and squirrels

34kurt3 years ago

5 0

The answer would be A.

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An atom contains one proton , one electron, and one neutron. Which two particles are most similar in mass

andrey2020 [161]

Proton and neutron, which are both approximately 1 amu

3 0

3 years ago

Read 2 more answers

Answer right = Brainliest!!

amid [387]

A b and e is are the answers

8 0

3 years ago

Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =

MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{c}$

For a general chemical reaction:

$aA+bB\rightleftharpoons cC+dD$

The expression for $K_{eq}$ is written as:

$K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

$2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)$

The expression of $K_c$ for above equation is:

$K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}$

We are given:

$[H_2S]_{eq}=0.671M$

$[O_2]_{eq}=0.587M$

$K_c=1.35$

Putting values in above expression, we get:

$1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}$

$[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M$

Hence, the equilibrium concentration of water is 0.597 M

8 0

3 years ago

What is the change of state involved in combustion of an alcohol and it’s entropy ?

Tanya [424]

Answer:

idkwhat is thr qution

Explanation:

4 0

3 years ago

9.05 mol of oxygen gas to g of oxygen gas

NARA [144]

Molar mass of oxygen gas:

O₂ = 16 * 2 = 32.0 g/mol

1 mole O₂ -------------- 32.0
9.05 mole O₂ ---------- ?

Mass = 9.05 * 32.0

Mass = 289.6 g of O₂

hope this helps!

7 0

3 years ago