After deprotonation of tannin, tannin (Ar-OH) is converted to $Ar-O^{-}Na^{+}$ salt which is soluble in water and $CO_{3}^{2-}$ is converted to $HCO_{3}^{-}Na^{+}$ which is also soluble in water

Explanation:

Sodium carbonate is a strong electrolyte which produces carbonate anion upon dissociation.
Carbonate ion is a strong conjugate base of weak acid $HCO_{3}^{-}$
After deprotonation of tannin, tannin (Ar-OH) is converted to $Ar-O^{-}Na^{+}$ salt which is soluble in water and $CO_{3}^{2-}$ is converted to $HCO_{3}^{-}Na^{+}$ which is also soluble in water
Balanced equation: $Ar-OH+Na_{2}CO_{3}\rightarrow Ar-O^{-}Na^{+}+Na^{+}HCO_{3}^{-}$
Mechanism has been shown below.

7 0

3 years ago

Question 2 Which models of the atom from task 1 are not supported by Rutherfordâ€™s experimental evidence? For each of these mod

kirill115 [55]

Answer:

Sorry I don't know.

Explanation:

I'm only in middle school.

8 0

2 years ago

Which of the following is true of liquids and solids?

gayaneshka [121]

The answer is D. This is because liquids take up the shape of the container they are in, so it is never definite. Where as solids stay the same shape.

3 0

3 years ago