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Margarita [4]
3 years ago
6

What fraction of the enzymes will be active at ph=4.07 explain?

Chemistry
1 answer:
Ratling [72]3 years ago
8 0
PH is the scale of measurement to check either the solution is acidic or basic. if the pH value is greater than 7, the solution is towards basicity and if the pH value is less than 7, the solution is towards acidity.
pKa is the dissociation constant and it is used to describe the change in pH value, when pKa is equal to pH: 50% of the ionizable group is protonated and 50% of the enzymes will be active.
So 50% of the enzymes will be active.
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Ethanol (c2h5oh) melts at -114c and boils at 78 c the enthalpy of fusion of ethanol is 5.02 kj/mol, and its enthalpy of vaporiza
vovikov84 [41]
<span>100 kilo joules There are several phases that this problem undergoes and the final answer is the sum of all the energy used for each phase. Phase 1. Heating of solid ethanol until its melting point. Phase 2. Melting of the ethanol until it's completely liquid. Phase 3. Heating of the liquid ethanol until it reaches its boiling point. Phase 4. Boiling the ethanol until it's completely vapor. To make things more interesting, some of our constant are per gram and some others are per mole. So let's calculate how many moles of ethanol we have. Atomic weight carbon = 12.0107 Atomic weight hydrogen = 1.00794 Atomic weight oxygen = 15.999 Molar mass ethanol = 2*12.0107 + 6*1.00794 + 15.999 = 46.06804 g/mol Moles ethanol = 75g / 46.06804 g/mol = 1.628026719 mol Phase 1. Use the specific heat of solid ethanol and multiply by the number of degrees we need to change by the mass we have. So 0.97 J/g*K * 75 g * (-114c - -120c) = 0.97 J/g*K * 75 g * 6K = 436.5 J Phase 2: Time to melt. Just need the moles and the enthalpy of fusion. So: 1.628026719 mol * 5.02 kJ/mol = 8.172694128 kJ Phase 3: Heat to boiling. Just like heating to melting, just a different specific heat and temperature 2.3J/g*K * 75g * (78c - -114c) = 2.3J/g*K * 75g * 192 K = 33120 J Phase 4: Boil it to vapor. Need moles and enthalpy of vaporization. So 1.628026719 mol * 38.56 kJ/mol = 62.77671027 kJ Now let's add them together: 436.5 J + 8.172694128 kJ + 33120 J + 62.77671027 kJ = 0.4365 kJ + 8.172694128 kJ + 33.120 kJ + 62.77671027 kJ =104.5059044 kJ Since the least precise datum we have is 2 significant figures, round the result to 2 significant figures, giving 100 kilo joules.</span>
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3 years ago
Count the number of each type of atom in the equation below, and then balance the equation. Write In the numbers of atoms and co
Studentka2010 [4]

Answer:

Balanced equation

CS2(l) + 3O2(g)------> CO2(g) + 2SO2(g)

Explanation:

For a chemical equation to be balanced, the number of atoms of each element on the left Hans side of the reaction equation must equal the number of atoms of that element on the right hand side of the reaction equation.

Atoms of oxygen are six on both sides of the reaction equation. Atoms of sulphur are two while there is only one atom of carbon on both sides of the reaction equation.

4 0
3 years ago
Read 2 more answers
Which process in the atmosphere is responsible for moving heat from warm equatorial regions to higher latitudes
Anni [7]

Answer:

Heat transfer in the atmosphere from the equatorial regions to higher latitudes occurs through the process of Convection

Explanation:

The equatorial regions of the earth's surface receive the most heat from the sun than any other region of the earth. This is because the are most directly in line with the direct heat from the sun.

Due to this heat from the sun, atmospheric air around the equatorial regions are hot and less dense than air in regions of higher latitudes, and thus, rises above the equator. The rising air at the equator is replaced by colder and denser air from higher latitudes north and south of the equator. As the rising air of the equatorial regions are being replaced by colder and denser air from higher latitudes, the hot and humid air moves away from the equator, toward regions of higher latitude, north and south thereby setting up a convection current of heat flow.

8 0
3 years ago
2.61 kilograms of water in a container have a pressure of 200 kPa and temperature of 200°C . What is the volume of this containe
Arisa [49]

<u>Answer:</u> The volume of the container is 2.8497m^3

<u>Explanation:</u>

To calculate the volume of water, we use the equation given by ideal gas, which is:

PV=nRT

or,

PV=\frac{m}{M}RT

where,

P = pressure of container = 200 kPa

V = volume of container = ? L

m = Given mass of water = 2.61 kg = 2610 g   (Conversion factor: 1kg = 1000 g)

M = Molar mass of water = 18 g/mol

R = Gas constant = 8.31\text{L kPa }mol^{-1}K^{-1}

T = temperature of container = 200^oC=[200+273]K=473K

Putting values in above equation, we get:

200kPa\times V=\frac{2610g}{18g/mol}\times 8.31\text{L kPa }\times 473K\\\\V=2849.7L

Converting this into cubic meter, we use the conversion factor:

1m^3=1000L

So, \Rightarrow \frac{1m^3}{1000L}\times 2849.7L

\Rightarrow 2.8497m^3

Hence, the volume of the container is 2.8497m^3

6 0
3 years ago
How many mol in 10 g of H2O
astraxan [27]
The amount of mol is equal to the mass divided by the molar mass. (n= m/M) The molar mass in this case is (1+1+16=) 18g/mol. The amount of mol is (10/18=) 0,56.
7 0
3 years ago
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