Answer:
The answer is "828.75"
Explanation:
Please find the correct question:
For W21x93 BEAM,
![Z_x = 221.00 in^3 \\\\\to \frac{b_t}{2t_f} =4.53\\\\\to \frac{h}{t_w}=32.3](https://tex.z-dn.net/?f=Z_x%20%3D%20221.00%20in%5E3%20%5C%5C%5C%5C%5Cto%20%5Cfrac%7Bb_t%7D%7B2t_f%7D%20%3D4.53%5C%5C%5C%5C%5Cto%20%5Cfrac%7Bh%7D%7Bt_w%7D%3D32.3)
For A992 STREL,
![F_y= 50\ ks](https://tex.z-dn.net/?f=F_y%3D%2050%5C%20%20ks)
Check for complete section:
![\to \frac{b_t}{2t_f} =4.53 < \frac{65}{\sqrt{f_y = 9.19}}\\\\\to \frac{h}{t_w} =32.3 < \frac{640}{\sqrt{f_y = 90.5}}](https://tex.z-dn.net/?f=%5Cto%20%5Cfrac%7Bb_t%7D%7B2t_f%7D%20%3D4.53%20%3C%20%5Cfrac%7B65%7D%7B%5Csqrt%7Bf_y%20%3D%209.19%7D%7D%5C%5C%5C%5C%5Cto%20%5Cfrac%7Bh%7D%7Bt_w%7D%20%3D32.3%20%3C%20%5Cfrac%7B640%7D%7B%5Csqrt%7Bf_y%20%3D%2090.5%7D%7D)
Design the strength of beam =![\phi_b Z_x F_y\\\\](https://tex.z-dn.net/?f=%5Cphi_b%20Z_x%20F_y%5C%5C%5C%5C)
![=0.9 \times 221 \times 50\\\\=9945 \ in \ \ kips\\\\=\frac{9945}{12}\\\\= 828.75 \ft \ kips \\](https://tex.z-dn.net/?f=%3D0.9%20%5Ctimes%20221%20%5Ctimes%2050%5C%5C%5C%5C%3D9945%20%5C%20in%20%5C%20%5C%20kips%5C%5C%5C%5C%3D%5Cfrac%7B9945%7D%7B12%7D%5C%5C%5C%5C%3D%20828.75%20%5Cft%20%5C%20kips%20%5C%5C)
Did not engineer cables factoring wind shear
Answer:
The correct approach is "12.56 Ω".
Explanation:
The given values are:
Frequency,
f = 100 Hz
Inductor length,
L = 20 mH
Now,
The inductive reactance will be:
⇒ ![X_L=2 \pi fL](https://tex.z-dn.net/?f=X_L%3D2%20%5Cpi%20fL)
On putting the estimated values, we get
⇒ ![=2 (3.14)\times 100\times 20\times 10^{-3}](https://tex.z-dn.net/?f=%3D2%20%283.14%29%5Ctimes%20100%5Ctimes%2020%5Ctimes%2010%5E%7B-3%7D)
⇒ ![=12.56 \ \Omega](https://tex.z-dn.net/?f=%3D12.56%20%5C%20%5COmega)