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3 years ago

What happens when any ray of light strikes a concave mirror, after passing through its focal point?

Physics

2 answers:

nekit [7.7K]3 years ago

6 0

Answer:

Option (D)

Explanation:

The rules to draw the ray diagrams for concave mirror are given below:

1. When a ray of light incident on the pole of concave mirror at an angle of incidence, then after reflection, the angle of incidence is equal to the angle of reflection.

2. When incident ray of light passes through the centre of curvature of the mirror, then the reflected ray retraces its path.

3. When the incident ray of light passing through the focus of the concave mirror, then after reflection the reflected ray becomes parallel to the principal axis and vice versa.

baherus [9]3 years ago

5 0

D) The reflected ray travels parallel to the principal axis

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3 years ago

A block of mass m sits at rest on a rough inclined ramp that makes an angle θ with the horizontal. What must be true about force

galina1969 [7]

Answer:

μ =tanθ

Explanation:=

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2 years ago

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Hooke's law. The distance d when a spring is stretched by a hanging objective varies directly as the weight w of the object. If

Fofino [41]

Hooke's law is F=-kx, which means the elastic force contained by the spring is a product of the distance it stretches and its spring constant, but the direction of the force is opposite that of the displacement. We calculate as follows:

(3 kg)(9.8 m/s^2) = -k(-0.38 m)
k = 77.4

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7 0

3 years ago

Difference between displacement and vector quantity

daser333 [38]

The only 'difference' is that they are different categories.

It's like asking "What's the difference between Susie and girl ?"

Or "What's the difference between Cadillac and car ?"

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5 0

3 years ago

A 920-kg compact car moving at 92 m/s has approximately 3,893,440 Joules of kinetic energy. What is the change in kinetic energy

tensa zangetsu [6.8K]

Answer:

Change in kinetic energy = 3297280 J

Explanation:

Given that,

Mass, m = 920 kg

Speed of a car, v = 92 m/s

Kinetic energy, K = 3,893,440 J

If the speed of a car, V = 36 m/s

Net kinetic energy is given by :

$K_n=\dfrac{1}{2}mV^2\\\\=\dfrac{1}{2}\times 920\times (36)^2\\\\K_n=596160\ J$

The change in kinetic energy = 3,893,440 - 596160

= 3297280 J

So, the change in kinetic energy of the car is 3297280 J.

3 0

2 years ago