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krek1111 [17]
3 years ago
5

At t = 0 the components of a radio-controlled car's velocity are vx = 0.5 m/s and vy = 1.2 m/s. Find the components of the car's

velocity at t = 2.6 s, given that the components of its average acceleration during this period are ax = 2 m/s2 and ay = -1 m/s2.
Physics
1 answer:
FinnZ [79.3K]3 years ago
5 0

Answer:

x-component of velocity = 5.7 m/s

y-component of velocity = -1.4 m/s          

Explanation:

Use first equation of motion to find components of velocity at a given time:

v = u + at

where, v is  the final velocity, u is the initial velocity, a is the acceleration and t is the time.

Given:

u_x= 0.5 m/s\\u_y=1.2 m/s\\a_x=2 m/s^2\\a_y=-1m/s^2\\t = (2.6-0)s =2.6 s

v_x=u_x+a_xt\\\Rightarrow v_x=0.5+2\times 2.6\\\Rightarrow v_x=5.7 m/s

v_y=u_y+a_yt\\\Rightarrow v_y=1.2-1\times 2.6\\\Rightarrow v_y=-1.4 m/s

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What happens to the volume of an ideal gas as temperature drops
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Consider the elementary gas-phase reversible reaction A 3C Pure A enters at a temperature of 400 K and a pressure of 10 atm. At
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Answer:

  • 39%

Explanation:

The equilibrium equation is:

          A\rightleftharpoons 3C

The initial concentration of A can be calculated from the ideal gas equation:

                 pV=nRT\\\\n/v=p/(RT)\\\\C_A=\dfrac{10atm}{0.08206(atm-dm^3/K-mol)/times 400K}\\\\C_A=0.304mol/liter

Determine the conversion of substance A to substance C using an ICE table and the Kc constant:

             A               ⇄          3C

I            0.304                        0

C             - x                          + 3x

E          0.304 - x                   3x

         K_c=0.25=\dfrac{(3x)^3}{(0.304-x)}

Solve for x:

You need to use a graphing calculator:

  • 108x³ = 0.304 - x
  • 108x³ + x - 0.304 = 0
  • x ≈ 0.1195 mol/liter

Then:

           C_A=0.304mol/liter-0.1195mol/liter=0.1845mol/liter\\\\C_C=3\times 0.304mol/liter=0.912mol/liter

The equilbrium conversion is:

           \% = [0.304mol/liter-0.1845mol/liter]/(0.304mol/liter)\times 100

           \% \approx 39\%

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