Let's balance step by step. We'll start with Iron (Fe) Fe2O3 + HCl --> FeCl3 + H2O We have 2 Fe on the left, and only one on the right, so we'll double the Fe on the right Fe2O3 + HCl --> 2FeCl3 + H2O Now we have six Cl on the right, and only one on the left, so we'll multiply the Cl by six on the left Fe2O3 + 6HCl --> 2FeCl3 + H2O Finally, we can balance the water, as we have 6 H and 3 O on the left, and 2 H and one O on the right, so we can triple the H2O on the right Fe2O3 + 6HCl --> 2FeCl3 + 3H2O The equation has been balanced.
