Here are the answers:
Tools that magnify object are the following: Telescope, microscope, binoculars and magnifying glass
Tools that don't magnify are the following: ruler, radio dish, and streak plate wind vane
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The Mr of 2MgSO4 is 240.6 g/mol
<u><em>calculation</em></u>
The atomic mass of 2MgSO4 = 2 ( atomic mass of Mg +atomic mass of S +atomic mass of 4 atoms of O)
from periodic table the atomic mass of Mg= 24.3 g/mol, s=32 g/mol,
O = 16 g/mol
Atomic mass of 2MgSO4 is therefore = 2 [ 24.3 +32 +( 16 x4)]
= 240.6 g/mol
Question:
Which of the following statements correctly describe(s) the driving forces for diffusion of Na+ and K+ ions through their respective channels? Select all that apply.
A)The diffusion of Na+ ions into the cell is facilitated by the Na+ concentration gradient across the plasma membrane.
B)The diffusion of Na+ ions into the cell is impeded by the electrical gradient across the plasma membrane.
C)The diffusion of K+ ions out of the cell is impeded by the K+ concentration gradient across the plasma membrane.
D)The diffusion of K+ ions out of the cell is impeded by the electrical gradient across the plasma membrane. The electrochemical gradient is larger for Na+ than for K+.
Answer:
"The concentration gradient and the electro-chemical gradient" describes the driving forces for diffusion of Na+ and K+ ions through their respective channels
Explanation:
The Na ions diffusion inside the cell is facilitated by the concentration gradient of the Na ions which is present across the plasma membrane. Hence, the diffusion of the K ions which is present outside the cell and will be impeded due to the electrical gradient which is present near the plasma membrane. Thus, the electro-chemical gradient is greater as compared to the Na ion than that of the K ion.
The formula of ionic compound made from sodium (Na) and iodine (l) is
NaI
<em><u>Explanation</u></em>
- An ionic compound is are compounds made up of ions.
- The ions are atoms or ions that loses electron to form cation or gain electron to form anion.
- Metal for this case loses electron while non metal gain electrons
- In Nal Na <em>( a Metal</em>) loses one electron while I <em>(non metal) </em>gain one electron to form an ionic compound.