Question

A charge is moving in a magnetic field that points to the left.

Answer 1

The charge experiences no magnetic force when it is moving to the left or to the right

Explanation:

The force experienced by a charge moving in a magnetic field is given by the equation

$F=qvB sin \theta$

where

q is the magnitude of the charge

v is its velocity

B is the strength of the magnetic field

$\theta$ is the angle between the directions of v and B

From the equation, we observe that:

• The force is zero when the charge is moving parallel (or anti-parallel) to the field, so when the angle between v and B is zero (or 180 degrees): $sin 0^{\circ} = 0$ ($sin 180^{\circ}=0$
• The force is maximum when the charge is moving perpendicular to the field, so when the angle between v and B is 90 degrees: $sin 90^{\circ}=1$

From the first observation, we can say therefore that the charge in the problem will experience no magnetic force when it is moving parallel (or anti-parallel) to the field. Since the magnetic field points to the left, this means that the charge will experience no force when it is moving in one of the following directions:

• To the left
• To the right

Learn more about magnetic fields:

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