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yKpoI14uk [10]
3 years ago
10

By what factor should the length of a simple pendulum be changed in order to triple the period of vibration?

Physics
1 answer:
kenny6666 [7]3 years ago
4 0

Answer:

increased by 9 times

Explanation:

As the period of a simple pendulum is defined as the following formula

T = 2\pi\sqrt{\frac{L}{g}}

where L is the length of the pendulum and g is the constant gravitational acceleration. Since L is under a square root, if you want to triple the period of vibration, L must be increased by 9 times so that \sqrt{9} = 3

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The distance between the centers of the wheels of a motorcycle is 156 cm. The center of mass of the motorcycle, including the ri
Drupady [299]

Answer:

a = 9.86 m/s²

Explanation:

given,

distance between the centers of wheel = 156 cm

center of mass of motorcycle including rider = 77.5 cm

horizontal acceleration of motor cycle = ?

now,

The moment created by the wheels must equal the moment created by gravity.

take moment about wheel as it touches the ground, here we will take horizontal distance between them.

then, take the moment around the center of mass. Since the force on the ground from the wheels is horizontal, we need the vertical distance.

now equating both the moment

m g d = F h

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so,

a = \dfrac{g\ d}{h}

a = \dfrac{9.8\times 0.78}{0.775}

a = 9.86 m/s²

4 0
3 years ago
What is question 22?
Fynjy0 [20]

the answer is a!! its pretty simple I just read the graph.
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3 years ago
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A solar-powered car is traveling at constant speed around a circular track. what happens to the centripetal acceleration of the
anyanavicka [17]
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5 0
3 years ago
How much force is required to accelerate a 2 kg mass at 3 m/s2
swat32

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3 years ago
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