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asambeis [7]
4 years ago
9

Which statements accurately describe satellite motion? Check all that apply.

Physics
2 answers:
kap26 [50]4 years ago
7 0
The correct answers are 1,4,5,6 
 <em />I know this is right.
EastWind [94]4 years ago
5 0

Answer:

Gravity is the only force acting on a satellite.

Circular orbits result from the interaction between gravity and inertia.

Gravity provides the centripetal force for satellites.

Satellites are in free fall around Earth or other central objects.

Explanation:

Due to gravity, which acts as a centripetal force, the satellite remains in orbit, otherwise the straight motion generated by inertia would take it out of course. If the satellite moves very fast, it will leave the orbit towards the depths of space. On the other hand, if it moves very slowly, gravity will bring it directly to Earth. When the balance between gravity and inertia is achieved, the satellite is still in free fall, but at a very small rate.

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_____________________________

[D. 2 protons, 2 electrons, and 1 neutron.]

As we know that, protons are embedded in the nucleus with neutron having no charge. So, nucleus has positive charge. Electrons are revolved around the nucleus of the atom. Proton has positive charge and electron has negative charge.

Number of proton = Number of electron.

Hence, both 2 protons and 2 electrons make the atom electrically neutral. So, the net charge of atom is 0. Neutron are the subatomic particle which has only mass.

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8 0
3 years ago
A heavy flywheel rotating on its central axis is slowing down because of friction in its bearings. At the end of the first minut
Soloha48 [4]

Answer:

ω₂ = 93.6 rev / min

Explanation:

ω₀ = 260 rev / min

ω₁ = 0.68*ω₀ = 0.68*(260 rev / min) = 176.8 rev / min

ω₂ = ?

t₁ = 1 min

t₂ = 2 min

We can apply the equation:

ω₁ = ω₀ + α*t₁     ⇒    α = (ω₁ - ω₀) / t₁  

⇒   α = (176.8 rev / min - 260 rev / min) / 1 min = - 83.2 rev / min²

then we can use the same formula, knowing the angular acceleration:

ω₂ = ω₀ + α*t₂   ⇒   ω₂ = (260 rev / min) + (- 83.2 rev / min²)*(2 min)

⇒   ω₂ = 93.6 rev / min

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4 years ago
A 357 kg box is pulled 8.00 m up a 30° frictionless, inclined plane by an external force of 4925 N that acts parallel to the pla
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3 years ago
Centripetal forces are always directed toward the (center, outside) of a circle.
dexar [7]

Answer:

Centripetal forces are directed toward the center of a circle.

Hope this helps.

Explanation:

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