1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andre45 [30]
3 years ago
9

A skateboarder, starting from rest, rolls down a 10.9-m ramp. When she arrives at the bottom of the ramp her speed is 6.74 m/s.

(a) Determine the magnitude of her acceleration, assumed to be constant. (b) If the ramp is inclined at 26.6 ° with respect to the ground, what is the component of her acceleration that is parallel to the ground
Physics
1 answer:
JulijaS [17]3 years ago
4 0

Answer:b

Explanation:b

You might be interested in
An experiment is designed to see if sleep affects the number of vocabulary words subjects can remember. The dependent variable i
Kaylis [27]

The dependent variable is: <em>"number of vocabulary words subjects can remember"</em>

<h3>Which is the dependent variable?</h3>

In an experiment, we basically see how changing one variable affects another variable.

In this case, the experiment is:

<em>" if sleep affects the number of vocabulary words subjects can remember."</em>

Then the hours of sleep would be the independent variable (the one that the scientist can change) and the number of vocabulary words subjects can remember is the dependent variable (that depends on the independent variable).

So the correct answer is:

<em>"number of vocabulary words subjects can remember"</em>

If you want to learn more about variables:

brainly.com/question/15246027

#SPJ1

7 0
2 years ago
2. Find the velocity when the displacement is 40 m and the time is 5 s.
LenKa [72]

Answer:

V=?

S= 40m

t=5s

V=S/t

V=40/5

V=8m/s

3 0
3 years ago
Help !
Black_prince [1.1K]
First off, you need to know the weight of the projectile, lift and drag coefficients something like a high Reynolds number is preferred, then use the gravitational constant of 9.8 meters per second squared those would be a good start to get closer to your goal
7 0
3 years ago
The different shapes of the moon seen from Earth are called
Anastaziya [24]

Answer:

phases of moon

Explanation:

.................

3 0
3 years ago
Read 2 more answers
If the distance between the Earth and Moon were half what it is now, by what factor would the force of gravity between them be c
hichkok12 [17]

Answer:

4

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

m_1 = Mass of Earth

m_2 = Mass of Moon

r = Distance between Earth and Moon

Old gravitational force

F_o=\dfrac{Gm_1m_2}{r^2}

New gravitational force

F_n=\dfrac{Gm_1m_2}{(\dfrac{1}{2}r)^2}

Dividing the equations

\dfrac{F_n}{F_o}=\dfrac{\dfrac{Gm_1m_2}{(\dfrac{1}{2}r)^2}}{\dfrac{Gm_1m_2}{r^2}}\\\Rightarrow \dfrac{F_n}{F_o}=\dfrac{\dfrac{Gm_1m_2}{\dfrac{1}{4}r^2}}{\dfrac{Gm_1m_2}{r^2}}\\\Rightarrow \dfrac{F_n}{F_o}=4

The ratio is \dfrac{F_n}{F_o}=4

The new force would be 4 times the old force

7 0
3 years ago
Other questions:
  • An overnight rainstorm has caused a major roadblock. Three massive rocks of mass m1=584 kg, m2=838 kg, and m3=322 kg have blocke
    9·1 answer
  • Ray run 30 N. 30 feet with in 30 feet so what is the distance
    14·1 answer
  • Light reflects off the surface of lake superior. What phase shift does it undergo?
    8·1 answer
  • When objects are charged by _______, they do not need to touch each other.
    11·1 answer
  • The size of the electrical potential is measured in
    9·1 answer
  • What is the gravitational force between two objects?​
    7·2 answers
  • Which situation results in the least attraction between two magnets?
    14·1 answer
  • Р.ЗА.3
    7·1 answer
  • Arrange the objects in order from greatst to least of potential energy assume that gravity is constant
    15·1 answer
  • A form of energy is stored in the bonds between atoms. What is the name for this stored energy?
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!