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Explanation:
<h3>
Answer:</h3>
0.0253 mol H₂O
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] 0.456 g H₂O (water)
<u>Step 2: Identify Conversions</u>
[PT] Molar Mass of H - 1.01 g/mol
[PT] Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
<u>Step 3: Convert</u>
- [DA] Set up:
- [DA] Multiply/Divide [Cancel out units]:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.025305 mol H₂O ≈ 0.0253 mol H₂O
ΔH2 = - δH1 δH2 = - 2 x δH1 δH2 = 2 x <span>δ</span>H1
Answer: YES! The given compound exhibit
Geometrical Isomerism.
Explanation:
In Geometrical Isomerism or
Cis-Trans Isomerism, isomers possess same molecular formula, same structural formula with a double bond and with a only difference in the arrangement of atoms or group of atoms about the double bond in
three dimensional space.
4,4-dimethylpent-2-ene (given problem) has two groups about the double bond i.e.
Methyl (CH₃-) and
tertiary Butyl [(CH₃)₃-C-]. In
cis configuration both groups are at same side of the double bond, while in
trans configuration both groups are located opposite to each other as shown below;