Answer:
Explanation:
a ) y = A sin(B) ; here B is the phase of the wave which moves so that it remains constant
ωt - kx = constant
differentiating on both sides
ωdt - kdx =0
ωdt = kdx
dx / dt = ω / k
wave velocity = ω / k
b ) ω = 14.5 rad / s ,
k = 18 rad / m
wave velocity = ω / k
= 14.5 / 18
= .805 m /s
80.5 cm / s
c )
Amplitude = A
= 9.5 m
Answer:
Friction Force
Explanation:
As we know that centripetal force is the product of mass and centripetal acceleration
so we know that
so here we have
so we have
This acceleration is given by the force which may be towards the center of the circular path
Here in the above case it is possible due to friction force.
Answer:
Absolute magnitude
Explanation:
The brightness a star would have if it were at 10 pc from Earth is called Absolute magnitude.
Answer:
Part a)
Part b)
Part c)
Speed is more than the required speed so it will reach the top
Explanation:
Part a)
As we know that there is no frictional force while block is moving on horizontal plane
so we can use energy conservation on the block
Part b)
If the track has average frictional force of 7 N then work done by friction while block slides up is given as
work done against gravity is given as
Now by work energy equation we have
Part c)
now minimum speed required at the top is such that the normal force must be zero
so here we got speed more than the required speed so it will reach the top
Answer:
421.83 m.
Explanation:
The following data were obtained from the question:
Height (h) = 396.9 m
Initial velocity (u) = 46.87 m/s
Horizontal distance (s) =...?
First, we shall determine the time taken for the ball to get to the ground.
This can be calculated by doing the following:
t = √(2h/g)
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) = 396.9 m
Time (t) =.?
t = √(2h/g)
t = √(2 x 396.9 / 9.8)
t = √81
t = 9 secs.
Therefore, it took 9 secs fir the ball to get to the ground.
Finally, we shall determine the horizontal distance travelled by the ball as illustrated below:
Time (t) = 9 secs.
Initial velocity (u) = 46.87 m/s
Horizontal distance (s) =...?
s = ut
s = 46.87 x 9
s = 421.83 m
Therefore, the horizontal distance travelled by the ball is 421.83 m