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Pani-rosa [81]
3 years ago
11

Why is it called field effect transistor​

Engineering
1 answer:
Mrac [35]3 years ago
5 0

Answer:

The field-effect transistor (FET) is a type of transistor which uses an electric field to control the flow of current.

FET is named field effect transistor as field effect is producing, but in BJT also field effect will produce. :)

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5. Switch a in the circuit has been open for a long time and switch b has been closed for a long time. Switch a is closed at t =
andriy [413]

Answer:

(a) 1/L∫Vdt; integral t [0,1]

(b) 1/L∫Vdt; integral t [ 1, infinity]

Explanation:

An Inductor current I, flowing through an inductor depends on the voltage, V, across the inductor and the inductance, L, of the inductor. The switch 1, 2 timing varies the voltage V with time t

The expression for inductor current is given as:

I= 1/L∫Vdt,

where I is equal to the current flowing through the inductor, L is equal to the inductance of the inductor, and V is equal to the voltage across the inductor.

The formula can also be written as:

I= I0 + 1/L∫Vdt, where I is inductor current at time t, and io is inductor current at t = 0. Time can be varied by controlling the switch

8 0
4 years ago
i need help with this asap plz help me i rlly need help plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
Mama L [17]

omg thank youuuuuuuuuuuuuuuu

5 0
3 years ago
Read 2 more answers
Pick a subjectarea/field/topic that you are interested in. For each of the following Bonham- Carver uses of GIS give an example
Vanyuwa [196]

Answer:

I hope following attachment will help you a lot!

Explanation:

3 0
3 years ago
The real power delivered by a source to two impedances, ????1=4+????5⁡Ω and ????2=10⁡Ω connected in parallel, is 1000 W. Determi
kirza4 [7]

Answer:

The question is incomplete, below is the complete question

"The real power delivered by a source to two impedance, Z1=4+j5⁡Ω and Z2=10⁡Ω connected in parallel, is 1000 W. Determine (a) the real power absorbed by each of the impedances and (b) the source current."

answer:

a. 615W, 384.4W

b. 17.4A

Explanation:

To determine the real power absorbed by the impedance, we need to find first the equivalent admittance for each impedance.

recall that the symbol for admittance is Y and express as

Y=\frac{1}{Z}

Hence for each we have,  

Y_{1} =1/Zx_{1}\\Y_{1} =\frac{1}{4+j5}\\converting to polar \\  Y_{1} =\frac{1}{6.4\leq 51.3}\\  Y_{1} =(0.16 \leq -51.3)S

for the second impedance we have

Y_{2}=\frac{1}{10}\\Y_{2}=0.1S

we also determine the voltage cross the impedance,

P=V^2(Y1 +Y2)

V=\sqrt{\frac{P}{Y_{1}+Y_{2}}}\\

V=\sqrt{\frac{1000}{0.16+0.1}}\\ V=62v

The real power in the impedance is calculated as

P_{1}=v^{2}G_{1}\\P_{1}=62*62*0.16\\ P_{1}=615W

for the second impedance

P_{2}=v^{2}*G_{2}\\   P_{2}=62*62*0.1\\384.4w

b. We determine the equivalent admittance

Y_{total}=Y_{1}+Y_{2}\\Y_{total}=(0.16\leq -51.3 )+0.1\\Y_{total}=(0.16-j1.0)+0.1\\Y_{total}=0.26-J1.0\\

We convert the equivalent admittance back into the polar form

Y_{total}=0.28\leq -19.65\\

the source current flows is

I_{s}=VY_{total}\\I_{s}=62*0.28\\I_{s}=17.4A

6 0
3 years ago
Describe the "Bauschinger Effect" on the stress strain behaviour of steel
Rom4ik [11]

Answer:

The Bauschinger effect is the directionally determined change in the elasticity limit of a metal or alloy after primary plastic deformation. If you first deform a metal in one direction so that it is plastically deformed and then deform it in the opposite direction, the elastic limit in the opposite direction is lower.

From the point of view of the dislocation mechanism of plastic deformation, the Bauschinger effect indicates that during repeated deformation, it is easier for dislocations blocked in front of obstacles to move in the direction opposite to their movement during preliminary plastic deformation.

7 0
4 years ago
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