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Pani-rosa [81]
3 years ago
11

Why is it called field effect transistor​

Engineering
1 answer:
Mrac [35]3 years ago
5 0

Answer:

The field-effect transistor (FET) is a type of transistor which uses an electric field to control the flow of current.

FET is named field effect transistor as field effect is producing, but in BJT also field effect will produce. :)

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Explain mathematically whether the divergence of the curl of a vector field is
svp [43]

Answer:

yes

Explanation:

6 0
2 years ago
An industrial plant consists of several 60 Hz single-phase motors with low power factor. The plant absorbs 600 kW with a power f
Gelneren [198K]

Answer:

(a) Q=332 kvar and C=5.66 uF

(b) pf=0.90 lagging

Explanation:

Given Data:

P=600kW

V=12.47kV

f=60Hz

pf_{old} =0.75

pf_{new} =0.95

(a) Find the required kVAR rating of a capacitor

\alpha _{old}=cos^{-1}(0.75) =41.41°

\alpha _{new}=cos^{-1}(0.95) =18.19°

The required compensation reactive power can be found by

Q=P(tan(\alpha_{old}) - tan(\alpha_{new}))

Q=600(tan(41.41) - tan(18.19))

Q=332 kvar

The corresponding capacitor value can be found by

C=Q/2\pi fV^{2}

C=332/2*\pi *60*12.47^{2}

C=5.66 uF

(b) calculate the resultant supply power factor

First convert the hp into kW

P_{mech} =250*746=186.5 kW

Find the electrical power (real power) of the motor

P_{elec} =P_{mech}/n

where n is the efficiency of the motor

P_{elec} =186.5/0.80=233.125 kW

The current in the motor is

I_{m} =(P/\*V*pf)

The pf of motor is 0.85 Leading

Note that represents the angle in complex notation (polar form)

I_{m} =(233.125/12.47*0.85)

I_{m}=18.694+11.586j A

Now find the Load current

pf of load is 0.75 lagging (notice the minus sign)

I_{load} =(600/12.47*0.75)

I_{load} =48.115-42.433j A

Now the supply current is the current flowing in the load plus the current flowing in the motor

I_{supply} =I_{m} + I_{load}

I_{supply}= (18.694+11.586)+(48.115-42.433)

I_{supply} =66.809-30.847j A

or in polar form

I_{supply} =73.58°

Which means that the supply current lags the supply voltage by 24.78

therefore, the supply power factor is

pf=cos(24.78)=0.90 lagging

Which makes sense because original power factor was 0.75 then we installed synchronous motor which resulted in improved power factor of 0.90

8 0
3 years ago
Unfiltered full wave rectifier with a 120 V 60 Hz input produces an output with a peak of 15V. When a capacitor-input filter and
Alborosie

Answer:

V_{pp}=2V

Explanation:

Source Voltage V= 120V

Frequency f=60Hz

Peak output voltage Vp=15V

Peak Output Voltage with filter V_p'=14V

Generally the equation for Peak to peak voltage is mathematically given by

V_p'=V_p-\frac{V_{pp}}{2}

Therefore

V_{pp}=2(V_p-v_p')

V_{pp}=2(15-14)

V_{pp}=2V

5 0
2 years ago
. Analyze the following scenarios and mention in which normal form it is with reason? a) Book- bookID bookTitle PublisherName Pu
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Answer:

You so good is ué KKKKKK a gente não não é possível que o seu ponto de vista da minha irmã me ligou

Explanation:

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8 0
3 years ago
A man can swim at 4 ft/s in still water. He wishes to cross tje 40-ft wide river to point B, 30 ft downstream. If the river flow
iVinArrow [24]

Answer:

v \approx 4.472\,\frac{ft}{s}, t = 10\,s

Explanation:

Since man and river report constant speeds and velocities are mutually perpendicullar, the absolute speed of the man is calculated by the Pythagorean Theorem:

v = \sqrt{(4\,\frac{ft}{s} )^{2}+(2\,\frac{ft}{s} )^{2}}

v \approx 4.472\,\frac{ft}{s}

The required time to make the crossing is:

t = \frac{40\,ft}{4\,\frac{ft}{s} }

t = 10\,s

6 0
3 years ago
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