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Black_prince [1.1K]
3 years ago
5

An object starts at position 12 on a horizontal line with a reference point of 0. What is the position of the object if it moves

14 units to the left?

Physics
2 answers:
Wittaler [7]3 years ago
8 0

-2 is the right answer

kolbaska11 [484]3 years ago
8 0

Answer:

The position of the object is -2

Explanation:

I add a picture of the situation in order to explain the question.

We are going to state the ''zero'' on a horizontal line. Then, we are going to state as positive the sense from left to right.

Now, if the object moves 14 units to the left , we need to subtract to the original position 14 units (because it will be a negative move given that the object is moving to the left) ⇒

12-14=-2

It new position will be at -2.

In general, the first step to solve this kind of exercises is to set a reference system. Then, it is very important to draw the situation.

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compared to an object that does not roll, but instead slides without friction, should a rolling object be released from the same
Zinaida [17]

Answer:

from a lesser hight

Explanation:

because you need less force

hope its right if it is mark brainlyest ;)

6 0
2 years ago
Un paracaidista desciende desde 6 000 m de altura. Si la masa, con su equipo, es de 65 kg, ¿cuánto valdrá su energía potencial e
iris [78.8K]

Explanation:

PRIMERO ENCUENTRAS EL PESO DEL PARACAIDISTA

F_{peso} = 65 kg(9.80 m/s^{2}) = 637 N

CON LA FÓRMULA DE LA ENERGÍA POTENCIAL

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3 0
3 years ago
The pirate ship tie at the amusement park is a giant pendulum that riders sit in. It swings back and forth, with a maximum veloc
kkurt [141]

Here as we know that there is no loss of energy

so we can say that maximum kinetic energy will become gravitational potential energy at its maximum height

So here we have

\frac{1}{2}mv^2 = mgh

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m = 8000 kg

now from above equation we have

\frac{1}{2}(8000)(20^2) = (8000)(9.8)h

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4 0
3 years ago
Read 2 more answers
SOMEONE PLEASE HELP PLEASE PLEASE
Black_prince [1.1K]
Ais the correct answer
4 0
2 years ago
The centripetal force acting on the space shuttle
tamaranim1 [39]

Answer:

(4) weight

Explanation:

The centripetal force acting on the space shuttle in orbit is given by:

F=m\frac{v^2}{r}

where

m is the mass of the shuttle

v is the tangential speed of the shuttle

r is the radius of its circular orbit

When the shuttle orbits the Earth, the centripetal force that keeps the shuttle in circular motion is given by the gravitational attraction between the shuttle and the Earth, which corresponds to the weight of the shuttle, and it is given by:

F=G\frac{Mm}{r^2}

where

G is the gravitational constant

M is the Earth's mass

And this force, therefore, corresponds to the centripetal force.

7 0
3 years ago
Read 2 more answers
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