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3 years ago

State 3 properties of airTry your best doesn't have to be all of them

1 answer:

8 0

<span>Air is a mix of gases that is composed out of about 1/5 oxygen and 4/5 nitrogen. Though air is made up of mostly nitrogen and oxygen, it also contains traces of water vapor, argon, carbon dioxide and other substances.</span>

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Please list the following for the Element, HYDROGEN

bagirrra123 [75]

Answer:

1 Proton, 1 Electron, No Neutrons

Group 1, Period 1

Gases

3 0

3 years ago

A simple and common technique for accelerating electrons is shown in the figure, where there is a uniform electric field between

Sunny_sXe [5.5K]

Answer : $4.483\times 10^{15}\ m/s^2$ .

Explanation:

It is given that,

Electric field strength, $E=2.55\times 10^{4}\ N/C$

We know that,

Charge of electron, $q=1.6\times 10^{-19}\ C$

Mass of electron, $m=9.1\times 10^{-31}\ kg$

From the definition of electric field, $F=qE$ ...............(1)

According to Newton's second law, F = ma..........(2)

From equation (1) and (2)

$ma=qE$

$a=\dfrac{qE}{m}$

$a=\dfrac{1.6\times 10^{-19}\ C\times 2.55\times 10^{4}\ N/C }{9.1\times 10^{-31}\ kg}$

$a=0.4483\times 10^{16}\ m/s^2$

$a=4.483\times 10^{15}\ m/s^2$

So, the horizontal component of acceleration of an electron is $4.483\times 10^{15}\ m/s^2$ .

Hence, it is the required solution.

7 0

3 years ago

A water wave has a speed of 22.0 meters/second if the wave frequency is 0.0680 hertz what is the wavelength

serg [7]

V = f(wavelength)
22.0 = 0.0680 (wavelength)
wavelength = 323.52 m

8 0

3 years ago

A 4.0-cm tall light bulb is placed at distance of 8.3 cm from a concave mirror having a focal length of 15.2 cm. Determine the i

scoundrel [369]

Answer: the image distance is -18, 28 cm this means behind of the concave mirror. The image size is 2.2 higher that the original so it has 8.8 cm with the same orientation as original and it is a virtual imagen.

Explanation: In order to sove the imagen formation for a concave mirror we have to use the following equation:

1/p+1/q=1/f where p and q represents the distance to the mirror for the object and imagen, respectively. f is the focal length for the concave mirror.

replacing the values we obtain:

1/8.3+1/q=1/15.2

so 1/q=(1/15.2)-(1/8.3)=-54.7*10^-3

then q=-18.28 cm

The magnification is given by M=-q/p=-(-18,28)/8.3= 2.2

We also add a picture to see the imagen formation for this case.

6 0

3 years ago

Compound axial member ABC has a uniform diameter of d = 1.50 in. Segment (1) is an aluminum [E1 = 10,000 ksi] alloy rod with a l

skad [1K]

Explanation:

Below is an attachment containing the solution.

5 0

3 years ago