Question

At what temperature (°C) will a 10.00 g sample of neon gas exert a pressure of 96.7 kPa in a

Answer 1

Answer : The temperature of neon gas will be, 221.0 K

Explanation :

To calculate the temperature of neon gas we are using ideal gas equation.

$PV=nRT\\\\PV=\frac{w}{M}RT$

where,

P = pressure of neon gas = 96.7 kPa = 0.955 atm

Conversion used : (1 atm = 101.3 kPa)

V = volume of neon gas = 9.50 L

T = temperature of neon gas = ?

R = gas constant = 0.0821 L.atm/mole.K

w = mass of neon gas = 10.00 g

M = molar mass of neon gas = 20 g/mole

Now put all the given values in the ideal gas equation, we get:

$(0.955atm)\times (9.50L)=\frac{10.00g}{20g/mole}\times (0.0821L.atm/mole.K)\times T$

$T=221.0K$

Therefore, the temperature of neon gas will be, 221.0 K