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Lisa [10]
3 years ago
5

The urinary system helps to maintain the proper pH (acid-base) balance of the

Chemistry
2 answers:
elena-s [515]3 years ago
6 0

the answer is BLOOD...

larisa [96]3 years ago
5 0
Body.................

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ElenaW [278]

Explanation:

hope the picture above help u understand:)

8 0
3 years ago
A chemist needs 1.25 moles of sugar to dissolve in 1 liter of water how many grams of sugar needed
sdas [7]

Answer:

The mass of sugar used is 427.5 grams.

Explanation:

The formula of common sugar is \mathrm{C_{12}H_{22}O_{11}}.

Its molar mass of molecule is 342 grams per mole.

The number of moles of sugar used is equal to '1.25'

\mathbf{Mole=\frac{Mass \ given \ in \ grams}{Molar \ mass \ of \ molecule \ in \ grams}}

\textrm{Mass in grams}=\textrm{Mole} \times \textrm{Molar mass of molecule in grams}

\textrm{Mass in grams}= 1.25\times342

\mathbf{Mass \ in \ grams=427.5 g}

(NOTE : <em>You can calculate molar mass by adding the mass of all the atoms present in the atom. </em>

<em>Mass of Oxygen (O) = 16  ;  Total number of Oxygen atoms present = 11</em>

<em>Mass of Hydrogen (H) =1  ;  Total number of Hydrogen Atoms present = 22</em>

<em>Mass of Carbon (C) = 12   ;  Total number of Carbon atoms present = 12</em>

<em>Total mass of molecule = 12 × 12 + 1 × 22 + 16 × 11 = 342</em>)

4 0
3 years ago
HELP QUICK I HAVE A QUIZ ITS JUST MULTIPLE CHOICE
melamori03 [73]

Answer:

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5 0
4 years ago
The formula C2H4 can be described as
Elden [556K]
It's describe as Ethylene
4 0
4 years ago
Read 2 more answers
2C4H10+13O2--&gt;8CO2+10H2O Using the predicted and balanced equation, How many Liters of CO2 can be produced from 150 grams of
Anna11 [10]

Answer:  233 L of CO_2 will be produced from 150 grams of  C_4H_{10}

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}  \text{Moles of} C_4H_{10}=\frac{150g}{58g/mol}=2.59moles

The balanced chemical equation is:

2C_4H_{10}+13O_2(g)\rightarrow 8CO_2+10H_2O  

According to stoichiometry :

2 moles of C_4H_{10} produce =  8 moles of CO_2

Thus 2.59 moles of C_4H_{10} will produce=\frac{8}{2}\times 2.59=10.4moles  of CO_2  

Volume of CO_2=moles\times {\text {Molar volume}}=10.4moles\times 22.4mol/L=233L

Thus 233 L of CO_2 will be produced from 150 grams of  C_4H_{10}

8 0
4 years ago
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