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labwork [276]
4 years ago
12

Two people pull on a horizontal spring that is attached to an immovable wall. Then, they detach it from the wall and pull on opp

osite ends of the horizontal spring. They pull just as hard in each case. In which situation, if either, does the spring stretch more?
Physics
1 answer:
zimovet [89]4 years ago
3 0

Answer:In first case

Explanation:

When two People pull the spring, let the applied force by each person be F_o

and spring constant of spring be k

so Total force is 2F_o

total extension according to Hooke's law is

x=\frac{2F_o}{k}

When they detach the spring and apply force in opposite direction then force on either side is F so net extension is

x'=\frac{F_o}{k}

so in first case there will be more extension

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Which refers to the amount of heat required to change the temperature of 1 gram of a substance by 1°c and is related to the chem
Bas_tet [7]

Answer:

specific heat capacity

Explanation:

this is the amount of heat required to raise 1g of a substance through 1k

please like and Mark as brainliest

5 0
3 years ago
Read 2 more answers
Fossil fuels has been used more in the existing world. Why?
Inga [223]

Answer:

fossil fuels are being used more because fossil fuels are of great importance because they can burn to produce a  significant amount of energy per unit mass the use of coal as a fuel prefates recorded history.

Explanation:

Hope this helps! :)

3 0
4 years ago
Calculate the electrostatic force that a small sphere A, possessing a net charge of 2.0 x 10^-6 Coulombs exerts on another small
Anni [7]

Answer:

F = 5.33*10^-4N

Explanation:

to find the electrostatic force you use the Coulomb's law, given by the formula:

F=k\frac{q_Aq_B}{r^2}

k: Coulomb's constant = 8.89*10^9 Nm^2/C^2

q_a: charge of A = 2.0*10^{-6}C

q_B: charge of B = -3.0*10^{-6}C

r: distance between the spheres = 10.0m

By replacing all these values you obtain:

F=(8.89*10^9Nm^2/C^2)\frac{(2.0*10^{-6}C)(-3.0*10^{-6}C)}{(10.0m)^2}=5.33*10^{-4}N

hence, the forcebetween the spheres is about 5.33*10^-4N

3 0
3 years ago
A 2.2 kg box is sliding along a frictionless horizontal surface with a speed of 1.8 m/s when it encounters a spring. (a) Determi
iogann1982 [59]

Answer:

a) k = 2851.2\,\frac{N}{m}, b) v = 0.54\,\frac{m}{s}

Explanation:

a) According to the Principle of Energy Conservation, the kinetic energy of the box is transformed into elastic potential energy.

\frac{1}{2}\cdot (2.2\,kg)\cdot (1.8\,\frac{m}{s} )^{2} = \frac{1}{2}\cdot k \cdot (0.05\,m)^{2}

The spring constant is:

k = 2851.2\,\frac{N}{m}

b) The initial speed needed to compress the spring by 1.5 centimeters is:

\frac{1}{2}\cdot (2.2\,kg)\cdot v^{2} = \frac{1}{2}\cdot (2851.2\,\frac{N}{m} )\cdot (0.015\,m)^{2}

v = 0.54\,\frac{m}{s}

5 0
4 years ago
If a car accelerates at a uniform 4.0 m/s, how long will it take to reach a speed of 36.0 m/s,
11111nata11111 [884]

Answer:

9s

Explanation:

v=u+at

36=0+4t

t=36-0/4

t=9s

5 0
3 years ago
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