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Kitty [74]
3 years ago
14

If a planet has a radius 20% greater than that of the Earth but has the same mass as the Earth, what is the acceleration due to

gravity at its surface?
Physics
2 answers:
djverab [1.8K]3 years ago
6 0

Answer:

6.81 m/s^2

Explanation:

Radius of planet, Rp = R + 0.2R = 1.2 R

where, R is the radius of earth

Mass of planet = mass of earth = M

Let g be the acceleration due to gravity and g' be the acceleration due to gravity on planet.

the formula for acceleration due to gravity on earth

g=\frac{GM}{R^{2}}   .... (1)

the formula for acceleration due to gravity on planet

g'=\frac{GM}{1.44R^{2}}   .... (2)

Divide equation (2) be equation (1)

g' = g / 1.44

g' = 9.8 / 1.44 = 6.81 m/s^2

Thus, the acceleration due to gravity on surface of planet is 6.81 m/s^2.  

Vaselesa [24]3 years ago
5 0

Answer:

g_2=6.8125 m^2/sec

Explanation:

We know that

Acceleration due to gravity g is given by the formula

g= \frac{GM}{r^2}

G= gravitational constant

M= mass of the Earth

r= radius of the earth

g_1 = GM/r_1^2

Let acc. due to gravity after radius is 20% greater be g_2

then

g_2=GM/r_2^2

=> g1/g2 = (r_2/r_1)^2 => g2 = 9.81/1.2^2 = 6.8125

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Answer:

a ) 11.1 *10^3 m/s = 39.96 Km/h

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Explanation:

a)v_{es} =v_{rms}= 11.1 km/s =11.1 *10^3 m/s = 39.96 Km/h

b)

M_O2 = 32.00 g/mol =32.0*10^{-3} kg/mol

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v_{rms} = \sqrt{ \frac{3RT}{M}}

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multiply each side by M_{o2}, so we have

v_{rms,o2}^2 *M_{o2} =3RT_{o2}

solving for temperature T_{o2}

T_{o2} = \frac{v_{rms,o2}^2 *M_{o2}}{3R}

In the question given,v_{rms} =v_{es}

T_{o2} = \frac{(11.1*10^3)^2 *32.0*10^{-3}}{3*8.31}

T_{o2} =1.58*10^5 K

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This ultimately implies that, a multiple point perspective is a system of perspective which is created with a number of vanishing points, that are usually created by multiple objects.

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2 years ago
When is Ampère’s Law valid? Evaluate all of the following statements, and explain your reasoning. a. When there is a high degree
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Answer:

Check Explanation

Explanation:

Ampere's Law gives the expression for the magnetic field produced by current in a current carrying material.

Mathematically, it is explained that the product of permeability and current is equal to the sum of the dot product of the magnetic field in the direction of the length elements and the length elements.

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This law is valid for infinite current carrying wires because the magnetic field around such infinite current carrying wire is symmetrical.

The magnetic field around a finite length of wire is non-symmetrical and the current isn't continuous.

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