If a planet has a radius 20% greater than that of the Earth but has the same mass as the Earth, what is the acceleration due to
2 answers:
Answer:
6.81 m/s^2
Explanation:
Radius of planet, Rp = R + 0.2R = 1.2 R
where, R is the radius of earth
Mass of planet = mass of earth = M
Let g be the acceleration due to gravity and g' be the acceleration due to gravity on planet.
the formula for acceleration due to gravity on earth
.... (1)
the formula for acceleration due to gravity on planet
.... (2)
Divide equation (2) be equation (1)
g' = g / 1.44
g' = 9.8 / 1.44 = 6.81 m/s^2
Thus, the acceleration due to gravity on surface of planet is 6.81 m/s^2.
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Answer:
a) x = 40 t , y = 39 t , z = 6 + 32 t - 16 t ², b) x = 80 feet , y = 78 feet , the ball came into the field
Explanation:
a) This is a projectile launch exercise, where in the x and y axes there is no acceleration and in the z axis the acceleration of the acceleration of gravity, let's write the equations of motion in each axis
Since the cast is in the center of the field, let's place the coordinate system
x₀ = 0
y₀ = 0
z₀ = 6 feet
x-axis (towards end zone, GOAL zone)
x = xo + v₀ₓ t
x = 40 t
y-axis (field width)
y = y₀ + t
y = 39 t
z axis (vertical)
z = z₀ + v_{oz} t - ½ g t²
z = 6 + 32 t - ½ 32 t²
z = 6 + 32 t - 16 t ²
b) The player catches the ball at the same height as it came out, so we can find the time it takes to arrive
z = 6
6 = 6 + 32 t - 16 t²
(t - 2)t = 0
t=0 s
t= 2 s
The ball position
x = 40 2
x = 80 feet
y = 39 2
y = 78 feet
the dimensions of the field from the coordinate system (center of the field) are
x_total = 150 feet
y _total = 80 feet
so we can see that the ball came into the field
Answer:
19.3m/s
Explanation:
Use third equation of motion
where v is the velocity at halfway, u is the initial velocity, g is gravity (9.81m/s^2) and h is the height at which you'd want to find the velocity
insert values to get answer