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Kitty [74]
3 years ago
14

If a planet has a radius 20% greater than that of the Earth but has the same mass as the Earth, what is the acceleration due to

gravity at its surface?
Physics
2 answers:
djverab [1.8K]3 years ago
6 0

Answer:

6.81 m/s^2

Explanation:

Radius of planet, Rp = R + 0.2R = 1.2 R

where, R is the radius of earth

Mass of planet = mass of earth = M

Let g be the acceleration due to gravity and g' be the acceleration due to gravity on planet.

the formula for acceleration due to gravity on earth

g=\frac{GM}{R^{2}}   .... (1)

the formula for acceleration due to gravity on planet

g'=\frac{GM}{1.44R^{2}}   .... (2)

Divide equation (2) be equation (1)

g' = g / 1.44

g' = 9.8 / 1.44 = 6.81 m/s^2

Thus, the acceleration due to gravity on surface of planet is 6.81 m/s^2.  

Vaselesa [24]3 years ago
5 0

Answer:

g_2=6.8125 m^2/sec

Explanation:

We know that

Acceleration due to gravity g is given by the formula

g= \frac{GM}{r^2}

G= gravitational constant

M= mass of the Earth

r= radius of the earth

g_1 = GM/r_1^2

Let acc. due to gravity after radius is 20% greater be g_2

then

g_2=GM/r_2^2

=> g1/g2 = (r_2/r_1)^2 => g2 = 9.81/1.2^2 = 6.8125

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Answer:

Explanation:

a )

change  in the gravitational potential energy of the bear-Earth system during the slide  = mgh

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b )

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then ,

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F x 11 = 4851 J -   756.9 J

= 4094.1 J

F = 4094.1 / 11

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