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Kitty [74]
2 years ago
14

If a planet has a radius 20% greater than that of the Earth but has the same mass as the Earth, what is the acceleration due to

gravity at its surface?
Physics
2 answers:
djverab [1.8K]2 years ago
6 0

Answer:

6.81 m/s^2

Explanation:

Radius of planet, Rp = R + 0.2R = 1.2 R

where, R is the radius of earth

Mass of planet = mass of earth = M

Let g be the acceleration due to gravity and g' be the acceleration due to gravity on planet.

the formula for acceleration due to gravity on earth

g=\frac{GM}{R^{2}}   .... (1)

the formula for acceleration due to gravity on planet

g'=\frac{GM}{1.44R^{2}}   .... (2)

Divide equation (2) be equation (1)

g' = g / 1.44

g' = 9.8 / 1.44 = 6.81 m/s^2

Thus, the acceleration due to gravity on surface of planet is 6.81 m/s^2.  

Vaselesa [24]2 years ago
5 0

Answer:

g_2=6.8125 m^2/sec

Explanation:

We know that

Acceleration due to gravity g is given by the formula

g= \frac{GM}{r^2}

G= gravitational constant

M= mass of the Earth

r= radius of the earth

g_1 = GM/r_1^2

Let acc. due to gravity after radius is 20% greater be g_2

then

g_2=GM/r_2^2

=> g1/g2 = (r_2/r_1)^2 => g2 = 9.81/1.2^2 = 6.8125

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Three 20.0 ohm resistors are
V125BC [204]

Answer:

6.67 ohm

Explanation:

From the question given above, the following data were obtained:

Resistor 1 (R₁) =20 ohm

Resistor 2 (R₂) = 20 ohm

Resistor 3 (R₃) = 20 ohm

Equivalent Resistance (R) =?

Since the resistors are arranged in parallel connection, the equivalent resistance can be obtained as follow:

1/R = 1/R₁ + 1/R₂ + 1/R₃

1/R = 1/20 + 1/20 + 1/20

1/R = (1 + 1 + 1) / 20

1/R = 3/20

Invert

R = 20/3

R = 6.67 ohm

Therefore, the equivalent resistance is 6.67 ohm.

5 0
2 years ago
An object is five focal lengths from a concave mirror.how do the object and image heights compare?
enot [183]

An object distance is presented as s = 5f and we know that the mirror equation relates the image distance to the object distance and the focal length.

The mirror equation is 1/f = 1/s + 1/s’ where the variable f stands for the focal length of the mirror. Variable (s) represents the distance between the mirror surface and the object and the variable <span>(s’) represents the distance between the mirror surface and the image. </span>

In addition, a concave mirror will have a positive focal length (f) and a convex mirror will have a negative focal length (f).

Now, we then have 1/f = 1/5f + 1/s’ which is s’ = 5f/4

Then we get the magnification ratio that expresses the size or amount of magnification or reduction of the object or image and to get the magnification, we use this equation: M= s’/s

M= 5f/4x5f

s’ = 1/4s

Therefore, the image height is one fourth of the object height

7 0
3 years ago
2. Is this chemical equation balanced?<br> 2C4H10 (g) + 13O2 (g) = 8CO2 (g) → 10H2O (l)
ehidna [41]
Yes that is a balaned equation
3 0
3 years ago
During a very quick stop, a car decelerates at 6.8 m/s^2. Assume the forward motion of the car corresponds to a positive directi
geniusboy [140]

Answer:

-24.28571 rad/s²

29.57239 revolutions

3.91176 seconds

52.026478 m

Explanation:

a_t = Tangential acceleration = -6.8 m/s²

r = Radius of wheel = 0.28

\omega_i = Initial angular velocity = 95 rad/s

\theta = Angle of rotation

\omega_f = Final angular velocity

t = Time taken

Angular acceleration is given by

\alpha=\frac{a_t}{t}\\\Rightarrow \alpha=\frac{-6.8}{0.28}\\\Rightarrow \alpha=-24.28571\ rad/s^2

The angular acceleration is -24.28571 rad/s²

\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2^2}{2\alpha}\\\Rightarrow \theta=\frac{0^2-95^2}{2\times -24.28571}\\\Rightarrow \theta=185.80885\ rad=185.80885\times \frac{1}{2\pi}\\\Rightarrow \theta=29.57239\ rev

The number of revolutions is 29.57239

\omega_f=\omega_i+\alpha t\\\Rightarrow t=\frac{\omega_f-\omega_i}{\alpha}\\\Rightarrow t=\frac{0-95}{-24.28571}\\\Rightarrow t=3.91176\ s

The time it takes for the car to stop is 3.91176 seconds

Linear distance

s=r\theta\\\Rightarrow s=0.28\times 185.80885\\\Rightarrow s=52.026478\ m

The distance the car travels is 52.026478 m

8 0
3 years ago
Which describes the best approach when conducting a scientific experiment
IgorC [24]

When conducting and experiment you want to have a notebook and something to write down notes with so you can keep everything organized and proper, and to not miss anything in the experiment. Also you want to have everything in order of the way it should be in.

I hope you found this helpful!

5 0
3 years ago
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