Given :
Capacitor , C = 55 μF .
Energy is given by :
.
To Find :
The current through the capacitor.
Solution :
Energy in capacitor is given by :
Now , current i is given by :
( differentiation of cos x is - sin x )
Therefore , the current through the capacitor is -11.18 sin ( 377t).
Hence , this is the required solution .
For the given problem it is necessary to recap the concepts about Power, that is, is the rate of doing work or of transferring heat, i.e. the amount of energy transferred or converted per unit time.
The equation for power can be written as
Where,
F= Net Force
V =Velocity
By the second newton law, force can be:
F = mg
Where m means the mass and g the gravity acceleration.
We can also write the equation as,
P = mgv
Replacing the values
P = 700*9.8*25
P = 17.15kW
Tenemos unidades en dos sistemas diferentes, por lo que convertimos los HP a Sistema internacional y tenemos que
1hp = 0.746kW
Then the fraction is,
Therefore the fraction of the engine power is being used to make the airplane climb is 22.984%