Answer:
(a) 10 s
(b) 236.5 m
(c) Kathy's speed = 47.3 m/s
Stan's speed = 42.9 m/s
Explanation:
<u>Given:</u>
= initial speed of Kathy = 0 m/s
= initial speed of Stan = 0 m/s
= acceleration of Kathy = 
= acceleration of Stan = 
<u>Assumptions:</u>
= final speed of Kathy when see catches Stan
= final speed of Stan when Kathy catches him
= distance traveled by Kathy to catch Stan
= distance traveled by Stan when Kathy catches him
= time taken by Kathy to catch Stan = 
= time interval in which Kathy catches Stan = 
Part (a):
Kathy will catch Stan only if the distances traveled by each of them are equal at the same instant.

Hence, Kathy catches Stan after 11 s from the Stan's starting times.
Part (b):
Distance traveled by Kathy to catch Stan will be distance the distance traveled by her in 10 s.

Hence, Kathy traveled a distance of 236.5 m to overtake Stan.
Part (c):

The speed of Kathy at the instant she catches Stan is 47.3 m/s.

The speed of Stan at the instant Kathy catches him is 42.9 m/s.
The answer is probably going to be b or d. hope that helped
Answer:
(a) 3.82 x 10⁷ m/s
(b) 4.5 MV/m
Explanation:
(a)
ΔV = change in the electric potential as the proton moves = 7.60 x 10⁶ Volts
q = magnitude of charge on proton = 1.6 x 10⁻¹⁹ C
v = speed gained by the proton
m = mass of proton = 1.67 x 10⁻²⁷ kg
Using conservation of energy
Kinetic energy gained by proton = Electric potential energy
(0.5) m v² = q ΔV
inserting the values
(0.5) (1.67 x 10⁻²⁷) v² = (1.6 x 10⁻¹⁹) (7.60 x 10⁶)
v = 3.82 x 10⁷ m/s
(b)
d = distance over which the potential change = 1.70 m
Electric field is given as
E = ΔV/d
E = 7.60 x 10⁶/1.70
E = 4.5 x 10⁶ V/m
E = 4.5 MV/m
<span>None bc gamma radio and light all have same speed</span>