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3 years ago

A boy is standing motionless on a skateboard. He throws a basketball forward. Describe his motion.

Physics

1 answer:

weqwewe [10]3 years ago

8 0

Answer:

Random motion

Explanation:

If the boy throws the basketball forward while at a position on the skateboard, the motion of the ball will be a random motion since we are not told if the ball is moving on a straight line when thrown forward.

In this case, the boy will tend to move in the direction of the ball. Since the ball is moving in a random manner, the motion of the boy will also be a random motion.

A random motion is a motion of a body in a zig zag manner. It is also known as Brownian motion e.g motion of a buzzing mosquito, motion of a smoke coming out of a chimney etc.

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A flat, wide cloud floats horizontally a few kilometers above the surface of Earth. Its lower surface carries a uniform surface

valentinak56 [21]

Answer:

$\frac{kQ}{r^2} r^$

Explanation:

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E= $\frac{kQ}{r^2} r^$

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3 years ago

Which astronomer spent 20 years plotting the positions of the planets

klio [65]

That was Tycho Brahe, and I thought it was actually more years than that.

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3 years ago

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Does a large object traveling slowly or a small object going fast have a greater momentum?

nekit [7.7K]

Answer:

It depends on the product of their mass and velocity

Explanation:

The momentum of a moving object is defined as the product of its mass and its moving velocity. So a same object would have larger momentum it's traveling faster, or gets heavier, and vice versa. In our case we don't have the exact value of speed and mass of both objects so we can't say which one has a greater momentum.

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3 years ago

An engine does 10 J of work and exhausts 25 J of waste heat during each cycle.

noname [10]

The thermal efficiency is defined as follows

$\eta = 1 - \frac{Q_{\text{out}}}{Q_\text{in}}$ ,

and the energy which is put into the system is

$Q_{\text{in}} = W_\text{out} + Q_\text{out}$ .

In your case $Q_\text{in} = 25 \text{ J},W_\text{out}=10 \text{ J}.$

So $Q_\text{out}=10 \text{ J}$ which gives an efficiency of

$\eta = 1 - \frac{10 \text{ J}}{25 \text { J}} = 0.6 = 60 \%$ .

4 0

3 years ago

A 0.25 kg arrow with a velocity of 12 m/s to the west strikes and pierces the center of a 6.8 kg target. What is the final veloc

Mademuasel [1]

Answer:20/47 meter per second

Explanation:

Mass of arrow(ma)=0.25kg

Velocity of arrow(va)=12m/s

Mass of target(mt)=6.8kg

Velocity of target(vt)=0 since target is at rest

Conservation of linear momentum says that :

maxva+mtxvt=(ma+mt)V

V=(maxva+mtxvt)/(ma+mt)

V=(0.25x12+6.8x0)/(0.25+6.8)

V=3/(7.05)

V=20/47 meter per second

4 0

3 years ago