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Rudiy27
3 years ago
5

how can you tell, as you walk close to a parked car, if it had been running recently? describe your reasoning in terms of energy

flows.
Physics
1 answer:
Blababa [14]3 years ago
4 0
This question is probably referring to heat energy transferring from the car to its surroundings.
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What is the amount of thermal energy needed to raise the temperature of 1 of a substance by ?
Goryan [66]

Answer:

It is the amount of energy required to raise the temperature of one gram of a substance by one degree Celsius.

Explanation:

Hope this helps and have a good day

7 0
3 years ago
A laborer pushes a box to distance of 20m. if the force required to push the box is 25N what will be the quantity of work done​
Marrrta [24]

Answer:

500 J

Explanation:

In the case of a rectilinear movement, the work is calculated as the product of Force (N) * movement (m). In your case, unless the angle between the force vector and the displacement vector is different from 0, the work is:

25 N * 20 m = 500 J

7 0
3 years ago
Select the correct answer.<br> Which word describes a goal that is poorly written?
siniylev [52]

Answer: The word is abstract.

Explanation:

8 0
3 years ago
A hot-water bottle contains 787 g of water at 75∘C. If the liquid water cools to body temperature (37 ∘C), how many kilojoules o
IgorC [24]

Answer:

Q = 787 gr * 1 \frac{cal}{gr C} *(37-75)C = -29906 cal

So then the answer for this case would be 29906 cal but we need to convert this into KJ and we know that 1 cal = 4.184 J and if we convert we got:

29906 cal *\frac{4.184 J}{1 cal}* \frac{1KJ}{1000 J}= 125.127 KJ

Explanation:

For this case we know the mass of the water given :

m = 787 gr

And we know that the initial temperature for this water is T_i =75 C.

We want to cool this water to the human body temperature T_f = 37 C

Since the temperatures given are not near to 0C (fusion point) or 100C (the boling point) we don't need to use latent heat, then the only heat involved for this case is the sensible heat given by:

Q= m c_p \Delta T

Where c_p represent the specific heat for the water and this value from tables we know that c_p =1 \frac{cal}{gr C} for the water.

So then we have everything in order to replace into the formula of sensible heat and we got:

Q = 787 gr * 1 \frac{cal}{gr C} *(37-75)C = -29906 cal

So then the answer for this case would be 29906 cal but we need to convert this into KJ and we know that 1 cal = 4.184 J and if we convert we got:

29906 cal *\frac{4.184 J}{1 cal}* \frac{1KJ}{1000 J}= 125.127 KJ

8 0
3 years ago
Read 2 more answers
11.76 cm² into two significant figures and include the appropriate units
PilotLPTM [1.2K]
You will need to turn this into scientific notation, so:

1.176 × 10^1 cm^2

To two significant figures means to two digits so since 7 is greater than 5, you will need to round up.

Final answer is:

1.2×10^1 cm^2
8 0
3 years ago
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