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3 years ago

5

how can you tell, as you walk close to a parked car, if it had been running recently? describe your reasoning in terms of energy

flows.

1 answer:

Blababa [14]3 years ago

4 0

This question is probably referring to heat energy transferring from the car to its surroundings.

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f an earthquake’s magnitude is measured based on the richter scale, how is this abbreviated? a. mr b. ms c. ml d. mb

zhannawk [14.2K]

The answer is A. Hope this helps!

5 0

2 years ago

A 20 Ohm resistance is connected

frutty [35]

Answer: 225 V

Explanation:

<u>Given:</u>

Secondary voltage,V2 = 150v

Resistance is connected across secondary winding,∴R2 = 20Ω

Supply current, ie, I1 = 5A

$\text{Now, secondary current,} \ $I_{2}=\frac{V_{2}}{R_{2}}=\frac{150}{20}=7.5$$$\therefore I_{2}=7.5 \mathrm{~A}$$For Transformers, we have $\frac{N_{2}}{N_{1}}=\frac{V_{2}}{V_{1}}=\frac{I_{1}}{I_{2}}$ so, Taking $\frac{N_{2}}{N_{1}}=\frac{l_{1}}{l_{2}}$ inserting all given \& obtained values, we get $\frac{N_{2}}{N_{1}}=\frac{5}{7.5}$$$\therefore \text { Turns ratio }=\frac{N_{1}}{N_{2}}=\frac{7.5}{5}=\frac{3}{2}=3: 2$$$

$\text{Again taking,}\frac{N_{1}}{N_{2}}=\frac{V_{2}}{V_{1}}$ \\So, \\$V_{1}=\frac{N_{1}}{N_{2}} V_{2}\\$ inserting all values, we get, $V_{1}=\frac{7.5}{5} * 150=225$\\Therefore, \fbox{Primary voltage, {$V_{1}=225 \mathrm{~V}$}}$

8 0

1 year ago

Coulomb is a very large unit for practical use. Justify your answer if 10^10 electrons are transferred from a body/second

zlopas [31]

Given:

10^10 electrons per second

To justify that coulomb is a very large unit for practical use, we need to convert the quantity of electron given to Coulombs:

From literature,

1 Coulomb is equivalent to 6.242×10^18 electrons<span>.

So,

= 10^10 electrons * (1 coulomb/</span><span>6.242×10^18</span> electrons) / second
<span>= 1.602 x 10^-9 coulumbs

This value is too small to be used in an actual setting.

</span><span>
</span>

3 0

3 years ago

An incandescent bulb produces 520 lumens and has an efficacy of 13 lm/W.

Mars2501 [29]

(520 lm) divided by (13 lm/W)

= (520 lm) times (W/13lm)

= (520/13) (lm · W / lm)

= 40 W

6 0

3 years ago

Read 2 more answers

The lesser the mass, the greater the acceleration for the given value of force. Why does this happen?

Tju [1.3M]

Newtons law states F=ma
so F/m=a
in addition it makes logical sense the lighter an object the easier it is to accelerate its velocity form 0 to some quantity

5 0

3 years ago