The compound Fe(NO2)2 is Iron (II) Nitrite.
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Answer: A volume of 455 mL from 0.550 M KBr solution can be made from 100.0 mL of 2.50 M KBr.
Explanation:
Given: 
= ?, 
= 0.55 M
= 100.0 mL, 
= 2.50 M
Formula used to calculate the volume of KBr is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that a volume of 455 mL from 0.550 M KBr solution can be made from 100.0 mL of 2.50 M KBr.
Answer:
It's 23.14 percent
Explanation:
First, the mass of all the elements are:
N = 14
O = 16
Fe = 56
In this molecule you have 3 atoms of N, and 9 atoms of O, so:
3•14 = 42
16•9 = 144
The whole mass of the molecule is:
56 + 42 + 144 = 242
242/100 = 2.42, so 1% is 2.42
56/2.42 = 23.14%
Answer:
The left side equation is:
![Ka = \frac{[CH_{3}COO^{-}] [H_{3}O^{+}]}{[HCH_{3}COO] [H_{2}O]}](https://tex.z-dn.net/?f=Ka%20%3D%20%5Cfrac%7B%5BCH_%7B3%7DCOO%5E%7B-%7D%5D%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%7D%7B%5BHCH_%7B3%7DCOO%5D%20%5BH_%7B2%7DO%5D%7D)
Explanation:
For the reaction of acetic acid HCH3CO2 with the water, The equilibrium constant equation is
The left side of this equilibrium constant equation will be written as shown below:
Answer:
d) 0.0962 L
Explanation:
The problem describes a <em>dilution process</em>, meaning that we can solve it by using the following equation:
Where subscript 1 stands for the volume and concentration of the concentrated solution, and 2 for those of the diluted solution. That means that in this case:
We <u>input the data</u>:
- 15.6 M * V₁ = 3.00 M * 500 mL
And <u>solve for V₁</u>:
Finally we <u>convert 96.2 mL to L</u>:
- 96.2 mL / 1000 = 0.0962 L
The answer is thus option d).
