Answer:
Gravitational force of attraction G(f) = 2.44 x 10⁻⁷ (approx.)
Explanation:
Given:
Mass M1 = 26 kg
Mass M2 = 5.1 kg
Distance r = 0.19 m
Find:
Gravitational force of attraction G(f)
Computation:
Gravitational force of attraction G(f) = G(m1)(m2)/r²
Gravitational force of attraction G(f) = [6.67 x 10⁻¹¹](26)(5.1)/(0.19)²
Gravitational force of attraction G(f) = 8.84 x 10⁻⁹ / 0.0361
Gravitational force of attraction G(f) = 2.44 x 10⁻⁷ (approx.)
The given sentence is part of a longer question.
I found this question with the same sentence. So, I will help you using this question:
For the reaction N2O4<span>(g) ⇄ 2NO</span>2(g), a reaction mixture at a certain temperature initially contains both N2O4 and NO2 in their standard states (meaning they are gases with a pressure of 1 atm<span>). If </span>Kp = 0.15, which statement is true of the reaction mixture before
any reaction occurs?
(a) Q = K<span>; The reaction </span>is at equilibrium.
(b) Q < K<span>;
The reaction </span>will proceed to
the right.
(c) Q > K<span>; The reaction </span>will proceed to the left.
The answer is the option (c) Q > K<span>; The reaction will proceed to the </span>left,
since Qp<span> = </span>1<span>, and 1 > 0.15.</span>
Explanation:
Kp is the equilibrium constant in term of the partial pressures of the gases.
Q is the reaction quotient. It is a measure of the progress of a chemical reaction.
The reaction quotient has the same form of the equilibrium constant but using the concentrations or partial pressures at any moment.
At equilibrium both Kp and Q are equal. Q = Kp
If Q < Kp then the reaction will go to the right (forward reaction) trying to reach the equilibrium,
If Q > Kp then the reaction will go to the left (reverse reaction) trying to reach the equilibrium.
Here, the state is that both pressures are 1 atm, so Q = (1)^2 / 1 = 1.
Since, Q = 1 and Kp = 0.15, Q > Kp and the reaction will proceed to the left.
Answer:

Explanation:
Hello.
In this case, since the acid is monoprotic and the KOH has one hydroxyl ion only, we can see that at the equivalence point the moles of both of them are the same:

Thus, since we are given 1.70 g of the acid, we compute the moles of acid that were titrated:

Which equal the moles of KOH. In such a way, since the molarity is defined as moles over liters (M=n/V), the liters are moles over molarity (V=n/M), thus, the resulting volume is:

Best regards!
Answer:
D. bromine
Explanation:
Highest electronegativity in the period has element closest to the *A group
K Ca Cu Br
chegg 2. What pattern did you observe measuring cell voltages with a silver electrode versus with a platinum/H2 electrode There is a difference of -0.786 V in silver
<h3>What is cell voltages ?</h3>
The difference in electric potential between two points, also known as voltage, electric potential difference, electric pressure, or electric tension, is what determines how much labor is required to move a test charge between the two sites in a static electric field. Volt is the name of the derived unit for voltage (potential difference) in the International System of Units. Joules per coulomb, or 1 volt equals 1 joule (of work) for 1 coulomb, is how work per unit charge is stated in SI units (of charge). The quantum Hall and Josephson effect was first employed in the 1990s, and most recently (in 2019), fundamental physical constants have been added for the definition of all SI units and derived units. Power and current were used in the previous SI definition for volt.
To learn more about cell voltages from the given link:
brainly.com/question/18938125
#SPJ4