Answer: 67.23 L
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
of particles.
To calculate the number of moles, we use the equation:
Putting in the values we get:
1 mole of methane occupies = 22.4 L
Thus 3 moles of methane occupy = 
Thus volume of 48 grams of methane gas is 67.23 L
1. B. Orbital Shape
2. C. counterclockwise
3. D. Electrons enter orbitals of lowest energy first
4. C. 6
5. C. 2
6. A. Filled energy sublevels
the answer is B because I jus did that
The answer is c the indicator will have different colors in the different solutions