A painter lifts a 2.8 kg bucket using a rope. if the acceleration of the bucket in 3.1 m/s2, what is the tension in the rope (in
n)? selected:
a. 27.4 n
b. 9.8 n
c. 8.68 n
d. 36.1 n
e. 2.94 n f. 0 n
a. 27.4 n
b. 9.8 n
c. 8.68 n
d. 36.1 n
e. 2.94 n f. 0 n
2 answers:
Refer to the diagram shown below
Given:
m = 2.8 kg, the mass of the bucket
a =3.1 m/s², the acceleration of the bucket
Therefore
W = 2.8*9.8 = 27.44 N, the weight of the bucket.
Let T = the tension in the rope.
From the free body diagram, the net force accelerating the bucket is
T - W = m*a
That is,
T = W + m*a
= 27.44 + 2.8*3.1 N
= 36.12 N
Answer: d. 36.1 N
Given:
m = 2.8 kg, the mass of the bucket
a =3.1 m/s², the acceleration of the bucket
Therefore
W = 2.8*9.8 = 27.44 N, the weight of the bucket.
Let T = the tension in the rope.
From the free body diagram, the net force accelerating the bucket is
T - W = m*a
That is,
T = W + m*a
= 27.44 + 2.8*3.1 N
= 36.12 N
Answer: d. 36.1 N
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Explanation:
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A ball is tossed straight up with an initial speed of 30 m/s
We need to find the height it will go and the time it takes in the air.
At its maximum height, its final speed, v = 0 and it will move under the action of gravity. Using equation of motion :
v = u +at
Here, a = -g
v = u -gt
i.e. u = gt
So, the time for upward motion is 3.06 seconds. It means that it will in air for 3.06×2 = 6.12 seconds
Let d is the maximum distance covered by it.
Putting all values
Hence, it will go to a height of 45.91 m and it will in the air for 6.12 seconds.